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Phantasy [73]
2 years ago
10

A solution containing HCI would likely have

Chemistry
2 answers:
riadik2000 [5.3K]2 years ago
8 0

Answer:

B on EDGE 2021

Explanation:

THE ANSWER ABOVE IS INCORRECT brainliest pls?

Temka [501]2 years ago
6 0

Answer:

b

Explanation:

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The highest pressure ever produced in a laboratory setting was about 2.0 x 10 6 atm. If we have a
tigry1 [53]

Answer:

Volume = 72.7272

Explanation:

if only pressure and volume change, then we can do some simple math to find the answer.

2 x 10 ^ 6 times 1 x 10 ^-5 = 20

pressure and volume must equal 20

20 = 0.275 x volume

20 / 0.275 = new volume

I don't remember significant digits but your volume is 72.72727272 just repeated

8 0
3 years ago
You are given an unknown type of clothing dye. how could you use the procedures in this lab to see if this dye is a mixture?
Arte-miy333 [17]
One separation technique to be used is the paper chromatography. This works by separating the components of the mixture through the difference of their concentrations. There is a stationary phase and the mobile phase, which flows through the stationary phase. The components travel at different rates and is usually signified by the colors. If more than one color would appear, that means that the dye is a mixture.
8 0
3 years ago
Read 2 more answers
6. If 4 mole of the rocket fuel ammonium perchlorate, NH4C/04 (s) is
Bond [772]

Answer:

144g of H₂O

Explanation:

3NH₄ClO₄(s) + 3Al → Al₂O₃(s) + AlCl₃(s) + 3NO(g) + 6H₂O(g)

From the equation:

3 moles of NH₄ClO₄ produced 6 moles of H₂O

4 moles of NH₄ClO₄ produced ? moles of H₂O

(4 ₓ 6)/3 = \frac{24}{3} = 8 moles of H₂O

1 mole of H₂O = (1 × 2) + 16 = 18g (The Relative Molecular mass of H₂O)

8 moles of H₂O = ?

Therefore 8 × 18 = 144g

=144g of H₂O

3 0
2 years ago
Balanced symbol equation for reaction between sodium carbonate solution and dilute sulphuric acid?
Dmitry [639]

Answer:

The molecular equation for the reaction betweensodium carbonate and sulfuric acid is: 1. Na2CO3(aq)+H2SO4(aq)→Na2SO4(aq)+CO2(g)+H2O(l) N a 2 C O 3 ( a q ) + H 2 S O 4 ( a q ) → N a 2 S O 4 ( a q ) + C O 2 ( g ) + H 2 O ( l ) .

Explanation:

3 0
3 years ago
Read 2 more answers
10. Isolation of a pure sample of the third product, which has been determined to be an isomer of the major and minor products,
Ymorist [56]

Answer:

Four possible isomers (1–4) for the natural product essramycin. The structure of compound 1 was attributed to essramycin by 1H NMR, 13C NMR, HMBC, HRMS, and IR experiments.

Explanation:

Three synthetic routes were used to prepare all four compounds (Figure 2A). All three reactions utilize 2-(5-amino-4H-1,2,4-triazol-3-yl)-1-phenylethanone (5) as the precursor, whereas each uses different esters (6–8) to construct the pyrimidinone ring. Isomer 1 was prepared by reaction A, which used triazole 5 and ethyl acetoacetate (6) in acetic acid. This was the reaction used in syntheses of essramycin by the Cooper and Moody laboratories.3,4 Reaction B produced compound 2 (minor product) and compound 3 (major product), which were separated chromatographically. This reaction allowed reagent 5 to react with ethyl 3-ethoxy-2-butenoate (7) in the presence of sodium in methanol, under reflux for 24 h. Compound 4 was prepared by reaction C, which was obtained by reflux of 5 and methyl 2-butynoate (8) in n-butanol.

7 0
3 years ago
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