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3 years ago

Please help. I'll mark you brainliest. ((:

1 answer:

5 0

I believe that if you shine a light in the front of a binocular, then the light would condense and be more pin-pointed while if you point it through the part where your eyes go the light would blow up. Either way, the light will be refracted once it travels through the lenses.

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According to the what the universe's total amount of energy does not change

RideAnS [48]

The Law of Conservation of Energy

8 0

3 years ago

6. A ball rolled 125 m from the top of a hill to the bottom of a hill. How long

leva [86]

Time = distance / speed
T = 125/ 5
T = 25 meters per second

7 0

3 years ago

After getting a haircut, Joey’s barber spins him around in his barber’s chair 2 times per second. Is period or frequency given?

Rzqust [24]

Answer:

Explanation:

This figure given is the frequency; 2 times per second represents frequency.

What is frequency?

It is the number of times per seconds something goes past or around another.

it is expressed as:

Frequency = $\frac{n}{t}$

where n is the number of turns

t is the time taken

Therefore, the Barber spinned him 2 times in 1 second.

The period is the inverse of frequency. It is the time taken for a body to go through a point;

Period = $\frac{t}{n } = \frac{1}{f}$ = $\frac{1}{2}$ s

7 0

4 years ago

What do these letters stand for<br> P=mv

victus00 [196]

Answer:

The equation for momentum of a piece of matter.

In either case, the momentum would be less than a linebacker hitting you at full speed. The equation for momentum is written: p = mv where p stands for momentum. That is, mass times velocity equals momentum.

Explanation:

Hope This Helps

Have A Great Day

4 0

2 years ago

a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cl

bekas [8.4K]

Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

$230=0+\dfrac{1}{2}\times9.8\times t^2$

$t=\sqrt{\dfrac{230\times2}{9.8}}$

$t=6.85 sec$

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

7 0

3 years ago