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svetoff [14.1K]
3 years ago
6

I NEED HELP ASAP IM ON TIMER !!!!

Physics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

a.) 20 km east

b.) 50 km west

c.) 80 km west

Explanation:

As given,

Railway station -     A            B              C

Distance(km) -       0            30             60

Starts from A , train reaches B be in 15 minutes

Starts from A , train reaches C be in 30 minutes

a.)

If A is origin

As train covers 30km = 15 minutes

⇒ 15 minutes = 30 km

    1 minute = \frac{30}{15} = 2 km

⇒ 10 minutes = 2×10 = 20 km

∴ we get

The position of the train moving from station A to station B after 10 minutes = 20 km east

b.)

If B is origin then , the position of  the train moving from station A to station B after 10 minutes = 30 + 20  = 50 km west

( Because B is the origin , so firstly train go from B to A in 15 minutes ( 30 km ) then A to B in 10 minutes (20 km) )

c.)

If C is the origin then , the position of  the train moving from station A to station B after 10 minutes = 60 + 20  = 80 km west

( Because C is the origin , so firstly train go from C to A in 30 minutes ( 60 km ) then A to B in 10 minutes (20 km) )

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Answer:

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A hollow spherical shell has mass 8.20 kg and radius 0.220 m. It is initially at rest and then rotates about a stationary axis t
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Answer:

8.91 J

Explanation:

mass, m = 8.20 kg

radius, r = 0.22 m

Moment of inertia of the shell, I = 2/3 mr^2

                                                    = 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2

n = 6 revolutions

Angular displacement, θ = 6 x 2 x π = 37.68 rad

angular acceleration, α = 0.890 rad/s^2

initial angular velocity, ωo = 0 rad/s

Let the final angular velocity is ω.

Use third equation of motion

ω² = ωo² + 2αθ

ω² = 0 + 2 x 0.890 x 37.68

ω = 8.2 rad/s

Kinetic energy,

K = \frac{1}{2}I\omega ^{2}

K = 0.5 x 0.265 x 8.2 x 8.2

K = 8.91 J

6 0
3 years ago
A roller coaster travels around a vertical 8-m radius loop. Determine the speed at the top of the loop if the normal force exert
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Answer:

v=10m/sec

Explanation:

From the question we are told that

Radius of vertical r= 8m

Force exerted by passengers is 1/4 of weight

Generally the net force acting on top of the roller coaster is give to be

F_N+Fg

where

F_N =forceof the normal

Fg= force due to gravity

Generally the net force is given to be FC(force towards center)

F_C =F_N + Fg

F_N =F_C -Fg

F_N=F_C-F_g

F_N=\frac{mv^2}{R} -mg

Mathematical we can now derive V

m_g + \frac{8m}{4}= \frac{mv^2}{8}

\frac{5mg}{4} =\frac{mv^2}{8}

v^2 =\frac{40*10}{4}

v=10m/sec

Therefore the speed of the roller coaster is given ton be v=10m/sec

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Answer:

The correct option is (d).

Explanation:

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Background research.
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