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Crank
2 years ago
13

An object is thrown upward with an initial velocity of 32.1 m/s. When the object reaches it maximum height, it is true of the ac

celeration, a, and the velocity, v, that: Group of answer choices
Physics
1 answer:
NARA [144]2 years ago
6 0

Answer:

At all times the acceleration a = -9.80 m/s^2   assuming 32.1 is chosen positive

At the top the velocity will be zero because the object is turning around

a = (v2 - v1) / t = -v1 / t since the velocity at the top is zero

t = -v1 / a = -32.1 / -9/8 = 3.26 sec      time to reach top

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What are some ways that electric fields are similar to magnetic fields?
sattari [20]

Answer:

The correct answers are the proportionality of the fields concerning distance, vector fields, and forces at a distance.

Explanation:

The similarities between magnetic fields and electric fields are that electric fields are produced by two charges that can be positive and negative. Magnetic fields are associated with two magnetic poles, although they are also produced by moving charges. Both fields are inversely proportional to the square of the distance between the sources, both fields are vectorial and both act by distant forces.

Have a nice day!

3 0
3 years ago
Anything that has mass and occupies space is defined as.
forsale [732]

Answer:

matter is the correct answer.

8 0
2 years ago
Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Y_Kistochka [10]

Answer:

Ro = 8.65 [g/cm³]

Explanation:

We must remember that density is defined as the ratio of mass to volume.

Ro=m/V

where:

m = mass = 0.450 [kg] = 450 [g]

V = volumen = 52 [cm³]

Ro = density [g/cm³]

Now replacing:

Ro = 450/52\\Ro = 8.65 [g/cm^{3} ]

8 0
2 years ago
You place a point charge q = -4.00 nC a distance of 9.00 cm from an infinitely long, thin wire that has linear charge density 3.
valentinak56 [21]

Answer:

F=6\times 10^{-7}\ N

Explanation:

Given:

  • quantity of point charge, q=-4\times 10^{-9}\ C
  • radial distance from the linear charge, r=0.09\ m
  • linear charge density, \lambda=3\times 10^{-9}\ C.m^{-1}

<u>We know that the electric field by the linear charge  is given as:</u>

E=\frac{\lambda}{2\pi.\epsilon_0.r}

E=\frac{1}{2}\times 9\times 10^9\times \frac{3\times10^{-9}}{0.09}

E=150\ N.C^{-1}

<u>Now the force on the given charge can be given as:</u>

F=E.q

F=150\times 4\times 10^{-9}

F=6\times 10^{-7}\ N

3 0
3 years ago
If a vibrating string is made shorter (i.e., by holding your finger on it), what effect does
Ghella [55]
  <span>Pitch and frequency are more or less the same thing - high pitch = high frequency. 
The freqency of vibration of a string f = 1/length (L) so as length decreases the frequency increases.</span>
4 0
3 years ago
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