Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:∠1 and ∠5
Step-by-step explanation:
(A) ∠3 and ∠6 forms the interior angles on the same side of the transversal. Thus, this option is incorrect.
(B) ∠1 and ∠4 forms the linear pair on the straight line a, thus this option is incorrect.
(C) ∠1 and ∠5 forms the corresponding angle pair, thus this option is correct.
(D) ∠6 and ∠7 forms the linear pair on the straight line a, thus this option is incorrect.
Answer:
8*8=64
Step-by-step explanation:
Don't worry! Keep on trying! I hope this helps! Have a great rest of your day!
Answer:
Alternate Interior Angles:
∠3 ≅ ∠5
Corresponding Angles:
∠3 ≅ ∠7
∠4 ≅ ∠8
Supplementary Angles:
∠3 is supplementary to ∠6
Step-by-step explanation:
Answer:
The value of 
. The figure is also attached below.
Step-by-step explanation:
Considering the expression
If we have to find the vale of 
, then
Therefore, the value of . The figure is also attached below.
Keywords: equation
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