Answer:
see below
Step-by-step explanation:
The formula for the sum of an infinite geometric series with first term a1 and common ratio r (where |r| < 1) is ...
sum = a1/(1 -r)
Applying this to the given series, we get ...
a. sum = 5/(1 -3/4) = 5/(1/4) = 20
b. sum = d/(1 -1/t) = d/((t-1)/t) = dt/(t-1)
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The derivation of the above formula is in most texts on sequences and series. In general, you write an expression for the difference of the sum (S) and the product r·S. You find all terms of the series cancel except the first and last, and the last goes to zero in the limit, because r^∞ → 0 for |r| < 1. Hence you get ...
S -rS = a1
S = a1/(1 -r)
First of its y-y1 = m(x-x1)
m is the slope, what it is increasing by.
y1 is the y intercept of your pair.
X1 is the x intercept of your coordinate pair, plug them in. If you dont know slope the formula to find it is:
y2-y1/x2-x1
The answer is C. Use the quadratic formula to solve it and you should be just fine!
6(x-2.5) ≥ 8-6(3.5+x)
A number is before a parenthesis. The first step is to multiply.
6(x-2.5) = 6x -15
8-6(3.5+x)
2(3.5+x)= 7+2x
6x-15≥7+2x
Now solve
6x-15≥7+2x
-2x -2x
(-2x+2x)= They cancel out
(6x-2x)= 4x
4x-15≥7
+15 +15
4x≥22
/4 /4
You get= x≥5.5
