Answer:
Cp = 0.237 J.g⁻¹.°C⁻¹
Explanation:
Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 640 J
m = mass = 125 g
Cp = Specific Heat Capacity = <u>??</u>
ΔT = Change in Temperature = 43.6 °C - 22 °C = 21.6 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 640 J / (125 g × 21.6 °C)
Cp = 0.237 J.g⁻¹.°C⁻¹
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,
HCl + H₂O ⇆ H₃O⁺ + OH⁻
In this case no salt is formed, so we can skip this option.
Ammonia being a weak base can abstract proton from HCl as follow,
HCl + NH₃ → NH₄Cl
Ammonium Chloride is a salt. So, among all four options, Option-C is the correct answer.
<u><em>Answer: Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products.</em></u>
Explanation:
Answer:
D, They produce fossil fuels
Explanation:
you can't just pull them out of nowhere
Answer:
At equilibrium, the concentration of
is going to be 0.30M
Explanation:
We first need the reaction.
With the information given we can assume that is:
+
⇄ 2
If there is placed 0.600 moles of NO in a 1.0-L vessel, we have a initial concentration of 0.60 M NO; and no
nor
present. Immediately,
and
are going to be produced until equilibrium is reached.
By the ICE (initial, change, equilibrium) analysis:
I: [
]=0 ; [
]= 0 ; [
]=0.60M
C: [
]=+x ; [
]= +x ; [
]=-2x
E: [
]=0+x ; [
]= 0+x ; [
]=0.60-2x
Now we can use the constant information:
![K_{c}=\frac{[products]^{stoichiometric coefficient} }{[reactants]^{stoichiometric coefficient} }](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5Bproducts%5D%5E%7Bstoichiometric%20coefficient%7D%20%7D%7B%5Breactants%5D%5E%7Bstoichiometric%20coefficient%7D%20%7D)
= 
= 
= 




At equilibrium, the concentration of
is going to be 0.30M