Answer:
The answer to your question is letter B
Explanation:
Incorrect name
A. acetic acid This name is correct for the acid with formula CH₃COOH
B. hydrocarbonate acid This is not the name for acid but for a molecule that has hydrogen and a metal.
C. hydrocyanic acid This name is correct for the inorganic molecule with formula HCN
D. sulfurous acid This name is correct and is the name of the inorganic molecule with formula H₂SO₃.
E. phosphoric acid This name is correct for the acid with formula H₃PO₄.
Explanation:
1. photosynthesis
2. Nucleus. The nucleus is the largest and most significant living organelle of the cell. ... Hence it is called brain or control centre of the cell.
3.Cytoplasm
Cells require a thick jelly-like substance that holds organelles in place inside the cell. This substance is known. Cytoplasm. Turgor pressure can help plants move.
4.Chloroplasts absorbing solar energy for cellular activities.
5.cell membrane
6.a.cell wall
b.chloroplast
c.large vacuole
Answer:
1.23 M
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of NaCl = 7.2 g
As we know , the molecular mass of NaCl = 58.5 g/mol
Moles is calculated as -
n = w / m = 7.2 g / 58.5 g/mol = 0.123 mol
Molarity is calculated as -
V = 100ml = 0.1 L (since , 1 ml = 1/1000L )
M = n / V = 0.123 mol / 0.1 L = 1.23 M
"A contactor is a electrically controlled switch which uses an electromagnetic coil to pull in the contacts.”
"A motor starter is a contactor, plus an overload relay that will drop out the coil voltage if the motor overloads. If there is not overload relay, it is not a starter any longer, it's back to being just a contactor."
Answer:
1.209g of MgO participates
Explanation:
In this problem, we have 0.030 moles of MgO that participates in a particular reaction.
And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.
To convert moles to grams we need to use molar mass of the compound:
<em>1 atom of Mg has a molar mass of 24.3g/mol</em>
<em>1 atom of O has a molar mass of 16g/mol</em>
<em />
That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol
And mass of 0.030 moles of MgO is:
0.030 moles MgO * (40.3g/mol) =
<h3>1.209g of MgO participates</h3>