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lisov135 [29]
3 years ago
14

How many electrons are there in an atom of carbon?​

Chemistry
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

if its a neutral atom there should be 6 electrons because there are 6 protons

Explanation:

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They were Native Americans.

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3 years ago
What would diluting the vinegar do to the rate of a reaction between vinegar and sodium hydroxide? decrease the rate of reaction
GarryVolchara [31]
Vinegar is aceti acid diluted in water.

The reaction of vinegar with sodium hydroxide is:

CH3COOH + NaOH ---> CH3COONa + H2O

That is an acid-base reaction.

The speed of reaction is proportional to the concentrations of the reactants.

Then, given thatn when you dilute the vinegar you decrease the concentration of CH3COOH, the rate of reaction will decrease.

Answer: decrease the rate of reaction.


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The balanced chemical equation for the complete combustion propane, C3H8 is: C3H8 + 5O2 → 3CO2 + 4 H2O How many moles of H2O wou
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8 0
3 years ago
Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
Use the scenario to answer the following question. Four scientists observed an area of land that had been cleared of all trees a
Blizzard [7]

Answer:

b

Explanation:t not sure

3 0
3 years ago
Read 2 more answers
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