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kherson [118]
2 years ago
10

The quadrilateral shown is a parallelogram. If AC = 28, what is the measure of AE?

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
5 0

Answer:

<h3>14</h3>

Step-by-step explanation:

Find the diagram of the parallelogram attached

According to the parallelogram shown, M is the midpoint of length of diagonal AC and BD.

If E is the midpoint of AC, then AE = EC and AE + EC = AC

Given AE + EC = AC

Substituting AE = EC into the formula, it becomes;

AE+AE = AC

2AE = AC

AE = AC/2

Given the length of side AC = 28;

AE = 28/2

AE = 14

Hence the measure of length AE is 14

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Answer:

Probability of having student's score between 505 and 515 is 0.36

Given that z-scores are rounded to two decimals using Standard Normal Distribution Table

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu (Mean) = 510, SD = 10.4 we have z(x) by using z(x) = (x - Mu)/SD as under:

In our case, we have x = 505 & 515

Approach 1 using Standard Normal Distribution Table:

z for x=505: z(505) = (505-510)/10.4 gives us z(505) = -0.48

z for x=515: z(515) = (515-510)/10.4 gives us z(515) = 0.48

Afterwards using Normal Distribution Tables and rounding the values to two decimals we find the probabilities as under:

P(505) using z(505) = 0.32

Similarly we have:

P(515) using z(515) = 0.68

Now we may find the probability of student's score between 505 and 515 using:

P(505 < x < 515) = P(515)-P(505) = 0.68 - 0.32 = 0.36

PS: The standard normal distribution table is being attached for reference.

Approach 2 using Excel or Google Sheets:

P(x) = norm.dist(x,Mean,SD,Commutative)

P(505) = norm.dist(505,510,10.4,1)

P(515) = norm.dist(515,510,10.4,1)

Probability of student's score between 505 and 515= P(515) - P(505) = 0.36

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