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iren [92.7K]
3 years ago
15

Find the zeros of the polynomial x^2 + 8x + 16

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

hey mate,

x^2 + 8x + 16 = 0

<=>

(x+4)^2 = 0

As we know that (a+b)^2 = a^2+b^2+2ab

then

(x+4)^2 = 0

<=> (x+4) = 0

<=> x = -4

so there is one solution x = -4

thanks

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