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3 years ago

The population of a town increased from 3500 in 2005 to 5600 in 2009. Find the absolute and relative (percent) increase.

Mathematics

1 answer:

Ket [755]3 years ago

6 0

Answer:

Absolute increase in population will be 2100

And percentage increase will be 60 %

Step-by-step explanation:

We have given population in 2005 is 3500

And population in 2009 is 5600

So absolute increase in population = 5600-3500 = 2100

We have to find the percentage increase in population

So relative percentage increase in population will be $\frac{2100}{3500}\times 100=60$ %

So population will increase by 60 %

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Step-by-step explanation:

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2 years ago

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2 years ago

The vertex of this parabola is at (-5,-2). when the x-value is -4, the y-value is 2. what is the coefficient of the squared expr

Westkost [7]

Vertex: (-5,-2); parabola opens up;

General form of the equation for a vertical parabola opening up is:

y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:

y+2 = a(x+5)^2. We need to find the value of the coefficient a.

From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).

subst. these values into y+2 = a(x+5)^2, we get:

10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or 1 = a(169/16).

Solving for a: a = 16/169 = 0.09, or approx 16/160, or 1/10. Unfortunately, this is not close to any of the four answer choices.

I thought it best to try again, and fortunately my second try was correct:

10+2 = a(13/4)^2, or (169/16)a. Thus, 12 = a(169/16)

12
Solving for a: a = ------------- = 1.14. The answer choice closest to this is 1.
169/16

Answer A is correct.

6 0

3 years ago

Read 2 more answers

6. (4.2.12) Of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired. a. F

nata0808 [166]

Answer:

(a) Probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is 0.2711.

Step-by-step explanation:

We are given that of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired.

Let Probability that item are defective = P(D) = 0.20

Also, R = event of item being repaired

Probability of items being repaired from the given defective items = P(R/D) = 0.60

So, Probability of items not being repaired from the given defective items = P(R'/D) = 1 - P(R/D) = 1 - 0.60 = 0.40

(a) Probability that a randomly chosen item is defective and cannot be repaired = Probability of items being defective $\times$ Probability of items not being repaired from the given defective items