C*h=area/2
type i am going to say acute triangle
We use the formule: t=S/v. So:
+ t1= 160/100 = 8/5 hrs = 5760''
+ t2= 160/90 = 16/9 hrs = 6400''
=> t2-t1= 6400 - 5760 = 640'' = 10'40''
Answer:
f(x) = x*3/4 + 42.5
Step-by-step explanation:
The original difference between the pair is 70 - 30 = 40
The new difference between the pair is 95 - 65 = 30
Since the differences are not the same, Mrs Bailey must first perform a (slope) multiplication by a factor of 30/40 or 3/4
Then 30 * 3/4 = 22.5
Then she can shift the scores up by 65 - 22.5 = 42.5 in order to get the range from 65 to 95
Therefore, f(x) = x*3/4 + 42.5. We can test that
f(30) = 30*3/4 + 42.5 = 65
f(70) = 70*3/4 + 42.5 = 95
Answer:
R-{13}
Step-by-step explanation:
We are given that
We have to find the domain of fog(x).
Domain of f(x)=R
Because it is linear function.
Domain of g(x)=R-{13}
Because the g(x) is not defined at x=13
fog(x) is not defined at x=13
Therefore, domain of fog(x)=R-{13}
