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2 years ago

Identify the terms and like terms in the expression.

Mathematics

1 answer:

AleksandrR [38]2 years ago

4 0

Answer:

terms: 2n, -n, -4, 7n

like terms: 2n, -n, 7n

Step-by-step explanation:

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Simplify the expression.

Naddika [18.5K]

Answer:

Step-by-step explanation:

((7x-4)^2) - (7x-4)(7x-4) + 3

(7x-4)(7x-4) is 7x-4^2

So its (7x-4)^2 - (7x-4)^2 + 3

(7x-4)^2 cancel out.

Answer is 3

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2 years ago

The process of digging a site includes a. carefully recording the location of artifacts. b. accurate descriptions of the artifac

Mice21 [21]

Answer:

The process of digging a site includes

D or B

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3 years ago

How much is 14 kg 450 gram less than 20 kg

Ipatiy [6.2K]

The answer.
14kg 450gram - 20kg = 5kg 550gram
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2 years ago

Read 2 more answers

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

Write an inequality. Thank you!<br><br> PLEASE ANSWER IMMEDIATELY!

guapka [62]

Answer:

m > 2

Step-by-step explanation:

Since it is an open dot, it is not greater than or equal to, but rather just greater than.

Then, since the arrow goes to the right, the equation is greater than.

8 0

3 years ago