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kondor19780726 [428]
3 years ago
10

Which relationships within the diagram are true? Check all that apply. △ACF ≅ △AEB because of ASA. △ACF ≅ △AEB because of SAS. △

ACF ≅ △AEB because of AAS. ∠CFA ≅ ∠EBA FC ≅ BE FC ≅ AC
Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

The correct answer is (A) △ACF ≅ △AEB because of ASA. (D) ∠CFA ≅ ∠EBA (E) FC ≅ BE

Step-by-step explanation:

∠CAF ≅ ∠EAB, Given that the angle AC ≅ AE; ∠ACD ≅ ∠AED, because is the same angle in Vertex A

Then we say, △ACF ≅ △AEB because of ASA has a coherent side (AC ≅ AE) and the two adjoining angles to this side are also coherent (∠ACD ≅ ∠AED and ∠CAF ≅ ∠EAB), then we say option (A) is true: △ACF ≅ △AEB because of angle side angle.

If the two triangles are coherent, then the FC ≅ BE; and ∠CFA ≅ ∠EBA, by CPCTC, then Options D and E are correct

Maksim231197 [3]3 years ago
7 0

Answer:

a, d , e

Step-by-step explanation:

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1.Multiply and simplify if possible.
vivado [14]

Answer:

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Step-by-step explanation:

Left Questions

One

sqrt(7)x ((sqrt(x) - 7sqrt(7) )                         Remove the Brackets

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This question has a a slight bit of ambiguity in it. Is the x outside the brackets underneath the root  sign or not? I have taken it as not. Leave a note if I am wrong. <em><u>Edit</u></em>: This question clears itself when you use the original statement. I think it is correctly represented now. When you use √ you have to use brackets to show what is under the root sign.

Two

You can take a lot of common factors out side the brackets.

The common factors are 3*sqrt(2)*a When you do that, you are left with

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Of course there are other, more direct ways of doing this.

Right Question.

The problem here is answering in such a way that you are showing work.

Let z = 3∛(2a)

The problem now becomes

z*(1 - 2)

- z

Now substitute back

-3∛(2a)      Answer

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