Solve the following linear programming problem.

Mathematics

1 answer:

Reil [10]3 years ago

8 0

Find the intersection point between the 2 restraint equations:

30 - 2x = 12 - \frac{1}{2} x \\ \frac{3}{2} x = 18 \\ x = 12

Substitute back in to find y-value:

y = 30 - 2(12) = 6

P is maximized at point (12,6)

P = 9(12)+9(6) = 162

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