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DerKrebs [107]
3 years ago
6

Which of the following is a biotic of an ecosystem a rock air grass climate

Chemistry
1 answer:
Zigmanuir [339]3 years ago
7 0
Grass is biotic- living.

please vote my answer brainliest. thanks!
You might be interested in
What is the volume in liters of 5.25 moles of He gas?​
serious [3.7K]

Answer:

\boxed {\boxed {\sf 117.6 \ L \ He}}

Explanation:

Regardless of the type of gas, 1 mole at standard temperature and pressure (STP) occupies a volume of 22.4 liters. In this case the gas is helium (He).

We can set up a ratio.

\frac { 22.4 \ L \ He}{ 1 \ mol \ He}

Multiply by the given number of moles.

5.25 \ mol \ He *\frac { 22.4 \ L \ He}{ 1 \ mol \ He}

The moles of helium will cancel.

5.25 *\frac { 22.4 \ L \ He}{ 1 }

5.25 * { 22.4 \ L \ He}

Multiply.

117.6 \ L \ He

5.25 moles of helium gas at STP is 117.6 liters of helium.

5 0
3 years ago
An aqueous solution is in equilibrium with a gaseous mixture containing an equal number of moles of helium, carbon dioxide, and
Sophie [7]

Answer:

[CO2] > [N2] > [He]

Explanation:

The relative concentration of CO2, N2 and He depends on the solubility of each gas in water. The more soluble in water a gas is, the greater its concentration in aqueous solution.

Among the gases listed, CO2 is most soluble in water hence it is expected to have the greatest concentration in solution followed by N2. Helium gas is insoluble in water hence it has the least concentration in the aqueous solution.

8 0
3 years ago
What kind of graph is this?
Novosadov [1.4K]
That is a bar graph.
3 0
3 years ago
Read 2 more answers
(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n
quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene =\frac{0.03 g}{78 g/mol}=0.0003846 mol

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

\frac{15}{5}\times 0.0003846 mol=0.0011538 mol of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0
3 years ago
CAN SOMEONE REWRITE/SHORTEN THIS FOR ME PLEASE? I'LL GIVE BRAINLIEST
Alex17521 [72]

Answer:

Here you go! 50% of your writing piece

Explanation:

Foods produced from or using GM organisms are often referred to as GM foods.

GM foods are developed and marketed because there is some advantage either to the producer or consumer of these GM foods. GM seed developers wanted their products to be accepted by producers and have concentrated on innovations that bring direct benefit to farmers and generally the food industry.

One objective for developing plants based on GM organisms is to improve crop protection. The GM crops currently on the market are mainly aimed at an increased level of crop protection through the introduction of resistance against plant diseases caused by insects or viruses or through increased tolerance towards herbicides.

Resistance against insects is achieved by incorporating into the food plant the gene for toxin production from the bacterium Bacillus thuringiensis. GM crops that inherently produce this toxin have been shown to require lower quantities of insecticides in specific situations, where pest pressure is high.

7 0
4 years ago
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