Answer :
will be 1 mole of
/ 125. 40 g of
Explanation : The molar mass and the formula units are the same thing in any compound so when given a molar mass of compound then one mole of that compound is divided by its molar mass. Where one mole will be equal to avogadro's number which is 6.022 X
.
The subscript 2 is the atomic number. This tells you the number of protons in the atom. The superscript 4 is the mass number. This tells you the protons + neurons
Answer:
(a) a carbon–carbon triple bond is shorter than a carbon–carbon single bond.
The given statement is true.This because bond order in of (C-C) bond in triple bond is 3 whereas the bond order of (C-C) bond in single bond is 1. Higher the bond order shorter will be the bond length.
(b) There are exactly six bonding electrons in the oxygen molecule.
The given statement is false. This is because bond order present in oxygen molecule is 2 which means there are 4 bonding electrons in the oxygen molecule.
(c) the (C-O) bond in carbon monoxide is longer than the (C-O) bond in carbon dioxide.
The given statement is false.This because bond order in of (C-O) bond in CO is 3 whereas in 
the bond order of (C-O) bond is 2. Higher the bond order shorter will be the bond length.
(d) The (O-O) bond in ozone is shorter than the (O-O) bond in oxygen.
The given statement is false. This is because bond order in of (O-O) bond in ozone molecule is 1.5 whereas in 
the bond order of (O-O) bond is 2. Higher the bond order shorter will be the bond length.
(e) The more electro-negative the atom, the more bonds it makes to other atoms.
The given statement is false. This is because atom with more electro-negative character. Since, they are highly electron rich atoms so they will tend to form less number of bonds with other atom.
Answer D.
The catalyst is not consumed during a chemical reaction, it just changes the path of the reaction to increase the rate of the chemical reaction by lowering the activation energy.
Answer:
25.0 mL
Explanation:
1. Gather the information in one place.
MM: 98.00 74.09
2H3PO4 + 3Ca(OH)2 → Ca3(PO4)2 + 6H2O
m/g: 8.85 15.76
V/mL: 350.0 550
2. Moles of H3PO4
n = 8.85 g × (1 mol/98.00 g) = 0.09031 mol H3PO4
3. Moles of Ca(OH)2
n = 15.76 g × (1 mol/74.09 g) = 0.2126 mol Ca(OH)2
4. Moles of Ca(OH)2 in 25.0 mL Solution
n = 0.2126 mol × (25.0 mL/550 mL) = 0.009 663 mol Ca(OH)2
5. Moles of H3PO4 needed
From the balanced equation, the molar ratio is 2 mol H3PO4: 3 mol Ca(OH)2
n = 0.009 663 mol Ca(OH)2 × (2 mol H3PO4/3 mol Ca(OH)2)
= 0.006 442 mol H3PO4
6. Volume of H3PO4
V = 0.006 442 mol ×( 350.0 mL/0.09031 mol) = 25.0 mL H3PO4
It will take 25.0 mL of the H3PO4 solution to neutralize 25.0 mL of the Ca(OH)2 solution.
