Answer:
2.1mol/L
Explanation:
Number of moles = 0.21 moles
Volume = 0.1L
Molarity of a substance is the number of moles of solute dissolved in a volume of solvent (L)
Molarity = number of moles / volume of solvent
Molarity = 0.21 / 0.1
Molarity = 2.1mol/L
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Answer:
1.25 gram of cesium-137 will remain.
Explanation:
Given data:
Half life of cesium-137 = 30 year
Mass of cesium-137 = 5.0 g
Mass remain after 60 years = ?
Solution:
Number of half lives passed = Time elapsed / half life
Number of half lives passed = 60 year / 30 year
Number of half lives passed = 2
At time zero = 5.0 g
At first half life = 5.0 g/2 = 2.5 g
At 2nd half life = 2.5 g/ 2 = 1.25 g
Thus. 1.25 gram of cesium-137 will remain.
Answer:
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