57 + x + x + 130 = 167
57 + 2x + 130 = 167
187 + 2x = 167
- 187 - 187
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2x = -20
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2 2
x = -10
<span>5(u+5)+p(u+5) = (u+5)(5+p)</span>
1 in 38.
Nothing much to say about this problem. There are 38 spaces on the roulette wheel and an every space on a fair wheel has an equal probability of being selected. So you would expect 1/38 = 0.026315789 = 2.6315789% of the time for the number 21 to show up.
Both Coordinates should be negative
1. negative
2. positive
3. positive
4. negative
5. positive