Answer:
The percentage of the scores lying between 450 and 750 is 49.4%
Step-by-step explanation:
In this question, we are simply asked to calculate the percentage of the scores lying between a particular range.
The first thing to do here is to calculate the z score of both scores
Mathematically, z score = (x - mean)/SD
for score 450, we have ; z = (450-450)/120 = 0/120 = 0
For score 750, we have z = (750-450)/120 =
2.5
Now, we move on to calculate the probability before turning it into a percentage.
The supposed probability we are to calculate is as follows;
P(450 < x < 750) or P(0 < z < 2.5)
Using standard score table, P = 0.49379
The percentage is thus 49.4%
First understand the concept values.
- x goes 2units right.
- Then it goes 3 units down.
From left to right the value is +ve
From up to down the value is -ve


H(x) = f(x)/g(x)
Use the quotient rule.
h '(x) = [g(x) f '(x) - f(x) g '(x)] / [g(x)]^2
=> h '(1) = [g(1) f '(1) - f(1) g '(1)] / [(g(1) ] ^2
h '(1) = [ 3*(-4) - 4*(-3)] / (3)^2 = [-12 + 12] / 9 = 0
Answer: 0
Answer:
A is the one that is true
Step-by-step explanation:
Because W is bigger than Z as it has the bigger proportion of the angle :)
Answer:
.
Step-by-step explanation: Given radical expression
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and

Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.</h3>