Answer:
I think you answered your own question
Let us assign the
recessive allele for freckle to be f and
the dominant F. According to the statement, we deduce that ff = 0.04.
The frequency of the recessive f allele is, therefore, is
0.2 (square root of 0.04 ).
Hardy-Weinburg p + q = 1
P + 0.2 = 1; p = 1- 0.2 = 0.8
Therefore using the Hardy-Weinburg equation of a population
in equilibrium
P2+2pq+q2=1
Heterozygous individuals are;
2pq = 2*0.8*0.2 = 0.32
This is 32% of the population
Answer:
No colonies, no growht.
Explanation:
The statement does not mention that apart from the GFP reporter gene, the plasmid contains ALSO the ampicillin resistance gene. This way, if you spread your traqnsformed cells on LB plates containing ampicillin, they will not be able to grow.
A more complex interconnected system of food chains is a consumer-resource system.
I don’t know
But I would help