First, you need to get the denominators (the bottom number) the same. The smallest number to get them to is 15.
So, what you need to do is take 2/5 and multiply the bottom by 3 to get 15, and since you did it to the bottom, you need to do it to the top too. So you would get, 6/15.
Then, for 1/3, take the bottom number and multiply it by 5. Then, since you did it to the bottom, do it to the top as well. You would get 5/15.
Then, you need to put them side by side. You don't add the bottom, so your denominator would remain 15, but your numerator (top) would get added.
<u> 6</u> + <u>5</u> = <u>11</u>
15 15 15
We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with

Answer:
The only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities.
Step-by-step explanation:
See the graph attached to this question.
The solution of the set of inequalities is given by the shaded region on the graph.
Now, the point (0,5) is outside this shaded region, hence it can not be the solution.
The point (3,0) also is outside this shaded region, hence it can not be the solution.
The point (-3,0) also is outside this shaded region, hence it can not be the solution.
Now, the only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities. (Answer)
I think it is 1200 people. Because if 40% are female and there are 480 females, then do 480 x 2 and that equals 960 then half of 480 is 240 so add 960 to 240 and you get 1200 as the total amount of people there. I'm not sure if it's right, but it should be.