All categories

4 years ago

How do you calculate the change in time?

Physics

2 answers:

3241004551 [841]4 years ago

7 0

Answer:

Δv ÷ Δt.

Explanation:

acceleration (a) equals change in velocity (Δv) divided by change in time (Δt), calculates the rate of change in velocity over time. This formula may be written a = Δv ÷ Δt.

Pani-rosa [81]4 years ago

3 0

Answer:

you divide the distance traveled by the rate

Explanation:

Rate of change in position, or speed, is equal to distance traveled divided by time. To solve for time, divide the distance traveled by the rate. For example, if Cole drives his car 45 km per hour and travels a total of 225 km, then he traveled for 225/45 = 5 hours.

You might be interested in

What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.49

Tomtit [17]

Answer:

i dk

Explanation:

6 0

4 years ago

If the coefficient of kinetic friction between a 22 kg kg crate and the floor is 0.27, what horizontal force is required to move

alina1380 [7]

Answer:

58.27 N

Explanation:

the data we have is:

mass: $m=22kg$

coefficient of friction: $\mu =0.27$

and we also know the acceleration of gravity is $g=9.81m/s^2$

We need to do an analysis of horizontal and vertical forces acting on the object:

-------

Vertically the forces acting on the object:

Normal force $N$ (acting up from the object)

weight: $w=mg$ (acting down from)

so the sum of forces in the vertical axis "y" are:

$F_{y}=N-w\\F_{y}=N-mg$

from Newton's second Law we know that $F=ma$ , so:

$ma_{y}=N-mg$

and since the object is not accelerating in the vertical direction (the movement is only horizontal) $a_{y}=0$ , and:

$0=N-mg\\N=mg$

-----------

now let's analyze the horizontal forces

frictional force: $f= \mu N$ and since $N=mg$ --> $f=\mu mg$

force to move the object: $F$

and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

$F=ma_{x}=F-f\\ma_{x}=F-\mu mg$

and we are told that the crate moves at a steady speed, thus there is no acceleration: $a_{x}=0$

and we get:

$0=F-\mu mg\\F=\mu mg$

substituting known values:

$F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N$

3 0

3 years ago

Your car is traveling behind a jeep. Both are moving at the same speed, so the velocity of the jeep relative to you is zero. A s

7nadin3 [17]

Answer:

No.

Explanation:

The spare tire is also moving at the speed of the jeep. When it separates from the jeep, both will be moving at the same horizontal speed, only that the spare tire will also fall at the same time. This if we neglect air friction, that could be a problem since it could cancel the horizontal velocity of the spare tire, although the jeep is blocking most of the air for the spare tire to feel any significant effect in such a short time.

6 0

3 years ago

Older railroad tracks in the U.S. are made of 12 m-long pieces of steel. When the tracks are laid, gaps are left between the sec

Shkiper50 [21]

Answer:

0.005 m

Explanation:

length of steel (L°) = 12 m

initial temperature (T) = 16 degrees

expected temperature (T') = 50 degrees

We can find how large the gaps should be if the track is not to buckle when the temperature is as high as 50 degrees from the formula below

ΔL = ∝L°ΔT where