The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.
Answer: coefficient of static friction
= 0.31
Explanation: Since they negotiate the curve without skidding, the frictional force (F1) equals the centripetal force (F2).
F1= uN
F2 = M*(v²/r)
M is the combined mass 450kg
V is the velocity 18m/s
r is the radius 106m
N is the normal reaction 4410N
u is the coefficient of static friction
Making u subject of the formula we have that,
u = {450*(18²/106)} /4410
=1375.47/4410
=0.31
NOTE: coefficient of friction is dimensionless. It as no Unit.
To solve this problem we will apply the concepts related to the conservation of momentum. That is, the final momentum must be the same final momentum. And in each state, the momentum will be the sum of the product between the mass and the velocity of each object, then


Here,
= Mass of each object
= Initial velocity of each object
= Final velocity of each object
When they position the final velocities of the bodies it is the same and the car is stationary then,

Rearranging to find the final velocity



The expression for the impulse received by the first car is


Replacing,


The negative sign show the opposite direction.
Answer:
A net torque applied to an object causes the angular velocity of the object to change.
Explanation:
The rotational equivalence of force is called a Torque. Thus, a net torque will make an object to rotate with an angular acceleration. Due tothe fact that all rotational motions have an axis of rotation, then a torque must be defined about a rotational axis. A force applied to a point on an object about the axis of rotation is known as a torque.
Answer:
(a) 
(b) 
Explanation:
Given:
Point source 
Distance from source Part a 
Distance from source Part b 
Solution:
Part (a)
Using intensity formula at distance L from an isotropic point.
-------------------(1)
Substitute
and
in equation 1..




Part (b)
Substitute
and
in equation 1.




Therefore, the intensity at distance 1.6 m from the source:
.
And, the intensity at distance 2.2 m from the source:
.