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Roman55 [17]
3 years ago
11

An objects motion changes

Physics
1 answer:
NARA [144]3 years ago
3 0

Answer:

uh finish the question please lol.

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How would you obtain a mean value for the specific heat<br> capacity of a material?
lidiya [134]
The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.
8 0
3 years ago
A Honda Hawk motorcycle and its rider with a combined mass of 450 kg travels around a curve of radius 106 m with a speed of 18 m
umka21 [38]

Answer: coefficient of static friction

= 0.31

Explanation: Since they negotiate the curve without skidding, the frictional force (F1) equals the centripetal force (F2).

F1= uN

F2 = M*(v²/r)

M is the combined mass 450kg

V is the velocity 18m/s

r is the radius 106m

N is the normal reaction 4410N

u is the coefficient of static friction

Making u subject of the formula we have that,

u = {450*(18²/106)} /4410

=1375.47/4410

=0.31

NOTE: coefficient of friction is dimensionless. It as no Unit.

7 0
3 years ago
A(n) 12500 lb railroad car traveling at 7.8 ft/s couples with a stationary car of 7430 lb. The acceleration of gravity is 32 ft/
navik [9.2K]

To solve this problem we will apply the concepts related to the conservation of momentum. That is, the final momentum must be the same final momentum. And in each state, the momentum will be the sum of the product between the mass and the velocity of each object, then

\text{Initial Momentum} = \text{Final Momentum}

m_1u_1 +m_2u_2 = m_1v_1+m_2v_2

Here,

m_{1,2}= Mass of each object

u_{1,2}= Initial velocity of each object

v_{1,2}= Final velocity of each object

When they position the final velocities of the bodies it is the same and the car is stationary then,

m_2u_2 = (m_1+m_2)v_f

Rearranging to find the final velocity

v_f = \frac{m_2u_2}{ (m_1+m_2)}

v_f = \frac{ 12500*7.8}{ 12500+7430}

v_f = 4.8921ft/s

The expression for the impulse received by the first car is

I = m_1 (v-u)

I = \frac{W}{g} (v-u)

Replacing,

I = \frac{12500}{32.2}(4.89-7.8)

I = -1129.65lb\cdot s

The negative sign show the opposite direction.

7 0
3 years ago
A net torque applied to an object causes __________. A net torque applied to an object causes __________. the angular velocity o
matrenka [14]

Answer:

A net torque applied to an object causes the angular velocity of the object to change.

Explanation:

The rotational equivalence of force is called a Torque. Thus, a net torque will make an object to rotate with an angular acceleration. Due tothe fact that all rotational motions have an axis of rotation, then a torque must be defined about a rotational axis. A force applied to a point on an object about the axis of rotation is known as a torque.

7 0
3 years ago
A 1.2 W point source emits sound waves isotropically. Assuming that the energy of the waves is conserved, find the intensity (a)
pshichka [43]

Answer:

(a) I = 3.7\times 10^{-2}\ W/m^{2}

(b) I = 1.9\times 10^{-2}\ W/m^{2}

Explanation:

Given:

Point source P_{b}=1.2\ W

Distance from source Part a L = 1.6\ m

Distance from source Part b L = 2.2\ m

Solution:

Part (a)

Using intensity formula at distance L from an isotropic point.

I = \frac{P_{b}}{4\pi(L)^{2}}  -------------------(1)

Substitute L = 1.6\ m and P_{b}=1.2\ W in equation 1..

I = \frac{1.2}{4\times 3.14(1.6)^{2}}

I = \frac{1.2}{32.15}

I = 0.037\ W/m^{2}

I = 3.7\times 10^{-2}\ W/m^{2}

Part (b)

Substitute L = 2.2\ m and P_{b}=1.2\ W in equation 1.

I = \frac{1.2}{4\times 3.14(2.2)^{2}}

I = \frac{1.2}{60.79}

I = 0.019\ W/m^{2}

I = 1.9\times 10^{-2}\ W/m^{2}

Therefore, the intensity at distance 1.6 m from the source:

I = 1.9\times 10^{-2}\ W/m^{2}.

And, the intensity at distance 2.2 m from the source:

I = 1.9\times 10^{-2}\ W/m^{2}.

7 0
3 years ago
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