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3 years ago

What factors affect the amount of solar energy that reaches earth's surface

Physics

2 answers:

zalisa [80]3 years ago

8 0

Weather
Particles in air such as smoke smog

bazaltina [42]3 years ago

7 0

Latitude~ due to earth spherical shape the solar rays have more intensity around the equatorial regions

cloud cover: clouds have a big impact on the amount of solar radition reaching earth surface

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The radius of the planent venus is nearly the same as that of the earth,but its mass is only eighty percent that of the earth. I

oee [108]

Weight=mg
g=GM/r^2
g on venus is 0.80w as radius is kept constant
m of object is kept constant
w α g
w(venus( is 0.8w

7 0

3 years ago

Read 2 more answers

Which one of the following statements about sulfuric acid is correct?

kherson [118]

The answer is C. Sulfuric Acid is dangerous to living organism

Direct contact with your skin and it will cause Chemical Burns , Direct contact with your eyes and it could cause a permanent Blindness.

This chemical also suck the water out of everything, so you can guess what will happen if it get into your body.

6 0

3 years ago

1) The energy held in the molecules that your lunch is composed of

Rasek [7]

Answer:

Chemical energy

Explanation:

The energy held in the foods molecules a lunch pack is composed of is chemical energy.

They occur within food substances which originates from plants and animals as giant organic molecules.

Since food is often derived from plants and animals.
Plants produce their own food by producing macromolecules from simple inorganic substances in the environment.
Animals takes up these food and build their own body through it.
Plants and animal parts constitutes organic molecules in which chemical energy is duly stored.
When the molecules are broken down, they released their chemical potential energy into heat energy.

4 0

3 years ago

A ship's anchor weighs 5000N. It's cable passes over a roller of negligible mass and is wound around a hollow cylindrical drum o

deff fn [24]

Hi! Great first step would be to understand the scenario (in my opinion). So two great ways would be to draw a picture or rephrase it. If something else works, do that! You just need to "see" the situation so that you can take some away from it.

Then I think a good next step is to conceptualize everything. Put everything into a context like a physics book would. The anchor is pulled 5000N downward - that's weight. The roller will act like a pulley, and we can ignore it's properties except that it's part of a pulley system (we can ignore stuff because it has "negligible" mass and no other details are given). And then we have the hollow cylindrical drum with one radius measurement given; so we can think of this as a made-up shape with mass - a cylindrical soda can without a top or bottom (but no thickness) and a 380kg mass. The anchor is drops 16m. It hints at energy. The energy that the drum gets is all do to this anchor pulling on the rope (which is really just a means of transferring force, since we neglect its mass and get no details).

Feel free to pause here to make sure you can get the scenario in your head.

So, we want to know something about the barrel as it's rolling. The rotation rate. How many turns per some time. But don't worry yet, we can find a way to work that in. Since the rope pulls and spins the drum, the drum is spun, and gets energy. One way to find the kinetic energy of the spinning drum uses the radius, mass, and rate of rotation. More on that soon.

And how does having some equation with the drum's kinetic energy, radius, mass, and rate of rotation help? Well, we can find all of those except our rate of rotation and solve for the rate of rotation. The energy is the only mystery, but that all comes from the dropping anchor. Can we find that energy? Yeah, there's a way to find the energy that gravity gives our anchor based on it's the force and how far that force moves it.

So, first for the anchor. Linear work is simple: $W=F d$
So you have your force and distance we associate with the anchor, so you have your work. We'll call that " $W_1$ " when we need it.

Next the drum's situation. Thanks to http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html, we have the equation for kinetic energy.
Generally, we have $KE=\frac12I\omega^2$ , and we need the " $I$ ," which deals with rotational inertia. That is pretty much how hard it is to rotate the drum based only on the idea that your getting the mass to move (acceleration). That site refers to our hollow drum as a "hoop," and gives says that we can consider the rotational inertia to be $I=MR^2$ . Now that we know the rotational inertia, we can use good old mathematical substitution to get the kinetic energy to look like
$KE=\frac12MR^2\omega^2$
And we can rearrange that to get
$\omega=\sqrt{\frac{2KE}{MR^2}}=\sqrt{\frac{2KE}{M}}\cdot\frac1R$

Since the energy change from the anchor's fall is the energy change of the drum, this $KE$ is the " $W_1$ " from before. So
$\omega=\sqrt{\frac{2W_1}{M}}\cdot\frac1R=\sqrt{\frac{2\left(F d\right)}{M}}\cdot\frac1R$

Now everything's set up. It's a matter of checking my work, carefully using a calculator, and making sure the answer makes sense (ie. this should be a lot of energy - much more than 1 Joule). Also, follow up by making sure you can do it again, alone. And feel free to ask or lookup questions you need along the way if there are missing pieces in your understanding.

Good luck! :)

5 0

3 years ago

Find the kinetic energy of a bullet weighing 0.10 N if its velocity is 2.0 X 103 m/s?

irina1246 [14]

The kinetic energy of the bullet is 20.4 kJ.

Explanation:

Kinetic energy of a bullet will be equal to the product of mass of the bullet with the square of velocity or speed of the bullet and then the half of that product value.

But here the mass of the bullet is not given, instead the weight of the bullet is given in terms of force. So from this, we have to first find the mass of the bullet.

We know that as per Newton's second law of motion, force is directly proportional to the product of mass and acceleration. So here the acceleration will be equal to the acceleration due to gravity as it is weight of the object.

So F = mg

0.10 N = m × 9.8

So ,the mass of the bullet is 0.0102 kg.

Now, we know the mass and velocity of the bullet is given as 2000 m/s.

So,

kinetic energy = $\frac{1}{2}$ × m × v²

kinetic energy = 0.5 × 0.0102 × 2000 × 2000 = 20.4 kJ

Thus, the kinetic energy of the bullet is 20.4 kJ.

5 0

3 years ago