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irakobra [83]
3 years ago
12

A stone is projected upward with a speed of 80.0 ft/s from a 224 ft high tower. Find the maximum height and the speed with which

it strikes the ground.
Physics
1 answer:
Over [174]3 years ago
6 0

Answer:

Maximum height: hmax= 323.45 ft.

Speed with wich it strikes the ground: Vf= 144.02 ft/s.

Explanation:

Vi= 80ft/s= 24.38 m/s

hi= 224 ft= 68.27 m

g= 9.8 m/s²

0= Vi - g*t

t(rise)= 2.48s

hmax = hi + Vi*t(rise) - g*t(rise)²/2

hmax= 98.59m = 323.45 ft

hmax= g*t²/2

t(fall)= √(2*hmax/g)

t(fall)= 4.48 s

Vf=g*t(fall)

Vf= 43.9 m/s= 144.02 ft/s

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Q=K_{tot}=K_A+K_B\\\\Q=K_A+0.5m_Bv_B^2\\\\Q=K_A+0.5m_B(\frac{m_A}{m_B})^2v_A^2\\\\\ But \ K_A=0.5m_Av_A^2\\\\\therefore Q=K_A+\frac{m_A}{m_B}K_A=K_A(1+\frac{m_A}{m_B})\\\\=Q=\frac{m_A+m_B}{m_B}K_A\\\\m_A=1836m_B\\\\\frac{K_A}{Q}=\frac{m_B}{1836m_B+m_B}=\frac{1}{1837}\\\\\frac{K_A}{Q}=5.444\times10^{-4}

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