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disa [49]
2 years ago
14

Which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)} Whic

h point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)}

Mathematics
2 answers:
myrzilka [38]2 years ago
7 0
(3,-6) because you can't have two of the same x's in a function
Lerok [7]2 years ago
3 0

<u>ANSWER</u>: Either (3,8) or (3,-6)


<u>Explanation</u>

For a relation to be a function, it must either be a one-to-one relation or many-to-one-relation.


The above relation is one-to-many relation because 3 is mapping on to -6 and 8.


To make the above relation a function, we must remove one of the points containing 3 as first coordinate.



This will make the relation one-to-one which then becomes a function.


See attachment for diagrammatic representation.

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If k(x) = 5x-6, which expression is equivalent to (k+k) (4)?
goldenfox [79]

Answer:

<em>5(4) - 6 + 5(4) - 6</em>

Step-by-step explanation:

k(x) = 5x - 6

(k+k)(x) = 5x - 6 + 5x - 6

(k+k)(4) = 5(4) - 6 + 5(4) - 6

=> Option D is correct

Hope this helps!

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Bingel [31]

Correct answer is: F(x)=-x^2-3

Step-by-step explanation:

We are given a function:

The graph of is also shown in the given question figure.

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General equation of parabola is given as:

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As seen from the question figure,

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creativ13 [48]

Hello from MrBillDoesMath!

Answer:

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Discussion:

The function value remains unchanged on [-2, 1] and decreases on [1,8]

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7 0
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Answer:

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Step-by-step explanation:

Remembering that Area = Length times Width, we factor the given function

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