(I)
Given equation is x²-8x = -16
⇛ x²-8x+16 = 0
⇛ x²-4x-4x+16 = 0
⇛ x(x-4)-4(x-4) = 0
⇛ (x-4)(x-4) = 0
⇛ x-4 = 0 or x-4 = 0
⇛ x = 4 or x = 4
(ii)
Given equation is x²+2x+1 = 0
⇛ x²+x+x+1 = 0
⇛ x(x+1)+1(x+1) = 0
⇛ (x+1)(x+1) = 0
⇛ x+1 = 0 or x+1 = 0
⇛ x = -1 or x = -1
(iii)
Given equation is 4x²-24x-36 = 0
⇛ 4(x²-6x-9) = 0
⇛ x²-6x-9 = 0
⇛ x²-2(x)(3) = 9
On adding 3² both sides then
⇛ x²-2(3)x)+3² = 9+9
⇛ (x-3)² = 18
⇛ (x-3) = ±√18
⇛ x-3 = ±√(2×9)
⇛ x-3 = ±3√2
⇛ x = 3±3√2
⇛ x = 3+3√2 or 3-3√2
If the gum costs 75 cents today, which is 3 cents less than three times what the pack cost 20 years ago, we just need to arrange what we know into an equation.
We know that the price of gum today is 75 cents, so we can leave that on one side of the equation as a constant. Also, since we are dealing only with cents and not dollars, there is no need to shift the decimal point to the left.
? = 75
Now, we can work the equation.
The problem tells us that 75 is 3 cents less than three times the old cost. So, if x is the old cost, we can work out the equation based on that.
It says that it's 3 cents less than 3 times x. The question is basically the equation in word form.
3x - 3 = 75
'3x' being the "three times the old cost" part, '- 3' being the "3 cents less" part, and '75' of course being the current price of a pack of gum.
Option C is your correct answer.
BTW if we were to solve this, we would see that the old price of a pack of gum is:
3x - 3 = 75
+ 3 + 3
3x = 78
/3 /3
x = 26
20 years ago, a 75-cent pack of gum cost 26 cents.
Hope that helped! =)
Answer:
40
Step-by-step explanation:
were
Each of them shakes hands with 109 others.
109*110 = 11990 handshakes were done.
Answer:y=-1/2
Step-by-step explanation:
125=(1/25)^(y-1)
5^3=(5^(-2))^(y-1)
5^3=5^(-2(y-1))
The same base eliminate each other we then have
3=-2(y-1)
3=-2y+2
Collect like terms
2y=2-3
2y=-1
Divide both sides by 2
2y/2=-1/2
y=-1/2
