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Elenna [48]
3 years ago
12

@bobross, @dqswag

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0
Basically, take the union of both domains g(x)=x/(1-x) 1-x=0 1=x x=1 is restricted because it makes you divide by 0 f(x)=(1-x)/(1+x) 1+x=0 x=-1 x=-1 is restricted because it makes you divide by 0 domain is all real numbers except -1 and 1
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Work out the size of AED. Work out x
Monica [59]

Answer:

a). m∠AED = 70°

b). x = 10°

Step-by-step explanation:

a). Quadrilateral ABDE is a cyclic quadrilateral.

Therefore, by the theorem of cyclic quadrilateral,

Sum of either pair of opposite angle is 180°

m(∠AED) + m(∠ABD) = 180°

m(∠AED) = 180° - 110°

m(∠AED) = 70°

Since, ∠AED ≅ ∠EAD

Therefore, m∠AED = m∠EAD = 70°

b). By triangle sum theorem in ΔABD,

m∠ABD + m∠BDA + m∠DAB = 180°

110° + 40° + m∠DAB = 180°

m∠DAB = 180° - 150°

m∠DAB = 30°

m∠BAE = m∠EAD + m∠BAD

              = 70° + 30° = 100°

By angle sum theorem in ΔACE,

m∠EAC + m∠AEC + m∠ACE = 180°

100° + 70° + x° = 180°

x = 180° - 170°

x = 10°

4 0
3 years ago
Explain how you could use a number line to determine -5 -(-3)<br><br> What is the difference?
AURORKA [14]

Answer:

The difference is -2

7 0
3 years ago
Which of the following numbers represents 8/9 to the nearest percent?
schepotkina [342]
The number that represents 8/9 to the nearest percent is .89
5 0
3 years ago
Aisha had a of ribbon. She used 15% of the ribbon to decorate cards and had 17 feet of ribbon left. She then used 20% of the rem
Tcecarenko [31]

Answer:

The total amount of ribbon she had was 35 feet of ribbon.

Step-by-step explanation:

I hope this is one of the answers and I hope this helps you.  Stay safe:)

3 0
2 years ago
Read 2 more answers
Hree people play a game in which one person loses and two people win each round. The loser must pay each winner the amount that
ipn [44]

Answer:

$7 ; $4 ; $3

Step-by-step explanation:

Given that:

1 player loses and 2 wins

Loser pays each winner amount each winner already has

3 rounds was played

At the end, each player has lost 1 round each and has $8.00

Since each player lost 1 round each, then each player won twice.

Given that the players are A, B and C

Starting from the last round :

Recall; they all have $8 after the last round.

If A lost the last round and pays B and C the amount they already have.

B and C finally have $8, Hence amount A paid B and C = 8/2 = $4 each

Hence, at the end of 2nd round / before last round :

A has ($8 paid + $8 final) = $16

B and C each have $4

End of first round before 2nd round of game:

If B lost, and pays A and C the amount they already have ;

A finally has 16 hence, amount B pays A = 16/2 = $8

Amount B pays C = 4/2 = $2

A = $8

B = $4 + $(8 + 2) = $14

C = $2

Ist round

C will lose :

Amount C pays B = $14 / 2 = $7

Amount C pays A = $8 /2 = $4

Hence, amount C has before round 1:

$7 + $4 + $2 = $13

Hence; Before the game ;

Either of the three players have ;

$7 ; $4 and $13

6 0
2 years ago
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