Mass of water produced : 0.146 g
<h3>Further explanation</h3>
Given
33.2 mL of 0.245 M lithium hydroxide
Required
mass of water
Solution
Reaction
HNO₃ (aq) + LiOH (aq) → H₂O (l) + LiNO₃ (aq)
mol LiOH :
= M x V
= 0.245 x 33.2 ml
= 8.134 mmol
From the equation, the mol ratio of HNO₃ : H₂O = 1 : 1, so mol H₂O = 8.134 mmol
mass H₂O :
= mol x MW
= 8.134 x 10⁻³ mol x 18 g/mol
= 0.146 g
-58 °C
The melting point is the same as the freezing point.
<span>In a popular classroom demonstration, solid sodium is added to liquid water and reacts to produce hydrogen gas and aqueous sodium hydroxide. Balanced chemical equation for this reaction is given below.
Na-sodium , H2o- water, H-hydrogen gas and NaOH- aqueous sodium hydroxide.
Two atoms of Na react with two atoms of water and this reaction will give us H (hydrogen gas) and two atoms of NaOH (aqueous sodium hydroxide).
2Na + 2 H2o = H2 +2NaOH.</span>
Answer:
0.18 mol
Explanation:
Given data
- Mass of carbon tetrachloride (solvent): 750 g
- Molality of the solution: 0.24 m
- Moles of iodine (solute): ?
Step 1: Convert the mass of the solvent to kilograms
We will use the relationship 1 kg = 1,000 g.
Step 2: Calculate the moles of the solute
The molality is equal to the moles of solute divided by the kilograms of solvent. Then,
