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saul85 [17]
3 years ago
10

Question 14(multiple choice worth 2 points) a student had a sample of pure water, and added an unknown substance to it. the stud

ent noticed that the hydroxide ion concentration in the solution increased as the substance was added. what is true about this newly formed solution? it is basic. it is acidic. it is a buffer. it has a ph of 7.
Chemistry
1 answer:
pantera1 [17]3 years ago
5 0
The answer is A its basic

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Morphine is a well known pain killer but is highly addictive. The lethal dose of morphine varies from person to person based on
Aliun [14]

Answer:

0.252 milimoles

Explanation:

To convert mass of a substance to moles it is necessary to use the molar mass of the substance.

The formula of morphine is C₁₇H₁₉NO₃, thus, its molar mass is:

C: 17*12.01g/mol = 204.17g/mol

H: 19*1.01g/mol = 19.19g/mol

N: 1*14g/mol = 14g/mol

O: 3*16g/mol = 48g/mol.

204.17 + 19.19 + 14 + 16 = <em>285.36g/mol</em>

Thus, moles of 71.891 mg = 0.071891g:

0.071891g × (1mol / 285.36g) = 2.5193x10⁻⁴ moles

As 1 mole = 1000 milimoles:

2.5193x10⁻⁴ moles = <em>0.252 milimoles</em>

7 0
3 years ago
A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
kaheart [24]

The equilibrium constant of the reaction is 282. Option D

<h3>What is equilibrium constant?</h3>

The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.

Concentration of bromine = 0.600 mol /1.000-L = 0.600 M

Concentration of iodine = 1.600 mol/1.000-L =  1.600M

In this case, we must set up the ICE table as shown;

              Br2(g) + I2(g) ↔ 2IBr(g)

I          0.6            1.6           0

C      -x                -x             +2x

E    0.6 - x         1.6 - x       1.190

If 2x = 1.190

x = 1.190/2

x = 0.595

The concentrations at equilibrium are;

[Br2] = 0.6 -  0.595 = 0.005

[I2] =   1.6 - 0.595 = 1.005

Hence;

Kc = [IBr]^2/[Br2] [I2]

Kc = ( 1.190)^2/(0.005) (1.005)

Kc = 282

Learn more about equilibrium constant:brainly.com/question/15118952

#SPJ1

4 0
2 years ago
What is the formula of the ionic compound composed of element X^2+ and element Y^-3?​
mihalych1998 [28]

Answer: X3Y2

Explanation:

The formula is

X has a valency of 2

Y has a valency of 3

So, we interchange the valencies

Therefore, the formula is

X3Y2

3 0
3 years ago
What two categorical ways of thinking about matter are discussed in the passage?
Mamont248 [21]

Answer:

There's no passage but I can say that matter are that ''thing'' which extend through all Universe, matter is everything. It can be seen or felt as liquid, gas or solid. This changes of its state depend on the amount of energy that is involved.

So, here is used categorical thinking because is a abstract concept that is hard to understand sometimes. It's abstract when we say that matter is all, not  just what we see, but even what we don't see like ''Dark Matter'', which is the majority in the Universe.

4 0
3 years ago
How many grams of NH3 are needed to provide the same number of molecules as in 0.85 grams of SF6?
solniwko [45]

Above it says the molecular weights are

NH3- 17g/mol and SF6-146 g/mol

Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.


<span><span><span>= 1mole / </span><span>146.048g *</span></span> 0.85g</span>


so we would need 0.00582000438 moles of NH3 to have the same number of molecules.

One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:


<span><span><span>= 17.030519999989988 g / </span><span>mole * </span></span>0.00582000438moles</span>


that equals 0.09911770099 grams.

so 0.09911770099 grams is the answer if you round that you get about 0.1 grams


3 0
3 years ago
Read 2 more answers
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