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Novay_Z [31]
3 years ago
15

Please hurry Participants in an informal discussion would most likely

Chemistry
2 answers:
Artist 52 [7]3 years ago
6 0
The answer is A informal is when you have a relaxed, friendly, or unofficial style, manner, or nature
Katyanochek1 [597]3 years ago
5 0
The answer is A. use casual, friendly conversation.
You might be interested in
PLEASE HELP!!!!!!!!! WILL MARK BRAINLIEST
frozen [14]

Answer:

19.278049929737628457607385688801

Explanation:

Volume = L * W * H

Volume = 17.78 * 9.21 * 4.45 = 728.70441

Density = Mass / Volume

Mass = 14,048

14,048 / 728.70441 = 19.278049929737628457607385688801

Density = 19.278049929737628457607385688801

7 0
3 years ago
Read 2 more answers
a substance is analyzed to have a percent composition of 74.186% sodium and 25.814% fluorine. calculate the empirical formula
Novosadov [1.4K]

Answer:

Na₂₆F₁₁

Explanation:

We find the moles of the substance assuming 100 g of the substance is present. Why do we take 100 g? Because then the percent of sodium/fluorine, would be the g of sodium/fluorine respectively:

74.186 g Sodium | 1 mol Sodium/23 g              =>       3.2255 mol Na    

25.814 g Fluorine | 1 mol Fluorine/19 g             =>       1.3586 mol F

Divide each by smallest number of moles:

3.2255/1.3586 = 2.37

1.3586/1.3586 = 1

Multiply by common number to get a smallest whole number:

2.37*11 = 26,

1*11 = 11

The empirical formula is Na₂₆F₁₁

5 0
3 years ago
A 0.25-mol sample of a weak acid with an unknown Pka was combined with 10.0-mL of 3.00 M KOH, and the resulting solution was dil
Masteriza [31]

Answer : The value of pK_a of the weak acid is, 4.72

Explanation :

First we have to calculate the moles of KOH.

\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}

\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol

Now we have to calculate the value of pK_a of the weak acid.

The equilibrium chemical reaction is:

                          HA+KOH\rightleftharpoons HK+H_2O

Initial moles     0.25     0.03        0

At eqm.    (0.25-0.03)   0.03      0.03

                     = 0.22

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[HK]}{[HA]}

Now put all the given values in this expression, we get:

3.85=pK_a+\log (\frac{0.03}{0.22})

pK_a=4.72

Therefore, the value of pK_a of the weak acid is, 4.72

7 0
3 years ago
If the volume of two containers stays the same , and one containers temperature is lowered, what happens to the pressure in the
melisa1 [442]
Gay-Lussacs law states that pressure is directly proportional to temperature at constant volume.
in this case the volumes of the 2 containers remain the same therefore volume is constant.
P/ T = k
where P - pressure, T - temperature and k - constant 
when temperature decreases the pressure too decreases and vice versa.
if temperature of one container is lowered the pressure also reduces.
since one containers temperature is lowered the pressure in that container reduces. 

answer is when temperature is lowered, pressure too is lowered. 
5 0
3 years ago
In what way are elements in the same column of the periodic table
andrew11 [14]
You can see wich group by the last out shell. Group 1 has 1 electron in the outershell
4 0
3 years ago
Read 2 more answers
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