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3 years ago

A solution has [oh−] = 4.0×10−8. what is the value of [h+] for the solution? answers

Chemistry

2 answers:

grandymaker [24]3 years ago

8 0

Answer: The pH of the solution is 6.68

Explanation:

To calculate the pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=4.8\times ^{-8}M$

Putting values in above equation, we get:

$pOH=-\log (4.8\times 10^{-8})\\\\pOH=7.32$

Calculating the pH of the solution:

$pH+pOH=14\\\\pH=14-7.32=6.68$

Hence, the pH of the solution is 6.68

Lelu [443]3 years ago

5 0

Answer is: the hydrogen ion concentration is 2.5·10⁻⁷ M.
[OH⁻] = 4·10⁻⁸ mol/L, equilibrium concentration of hydroxide anion.
[H⁺] is the equilibrium concentration of hydrogen ions.
[OH⁻] · [H⁺] = 10⁻¹⁴ mol²/L², ionicproduct of water on room temperature.
[H⁺] = 10⁻¹⁴ mol²/L² ÷ 4·10⁻⁸ mol/L.
[H⁺] = 2,5·10⁻⁷ mol/L = 0,00000025 mol/L.

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Three other application of Bernoulli's principle ?

Makovka662 [10]

<h2>Answer:</h2>

Bernoulli's Theorem in a general sense relates the weight, speed, and rise in a moving fluid (liquid or gas), the compressibility and consistency (internal grinding) of which are insignificant and the flood of which is predictable, or laminar.

(1): We can discover the speed of Efflux of a fluid.

This is given by v= sqrt (2gh), where the fluid is turning out from an opening in a vessel at profundity h from free fluid surface. This condition is known as Torricelli's hypothesis.

(2): Vena Contracta: The fluid stream from gap contracts at a separation minimal outside the opening to a neck, called Vena Contracta.

The territory of cross-segment of a fly is littler than a zone of opening. From this reality, we can discover the coefficient of withdrawal.

(3) : Bernoulli's standard is utilized in the development of Venturimeter, an instrument for estimation of measure of a stream of a fluid through a pipe.

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3 years ago

When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of

Anastaziya [24]

Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)

Step : Put a 3 in front of CO2 (g) to balance C

=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H

Step 2: Put a 4 in front of H2O

=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)

Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:

=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)

You can verify that the equation is balanced.

So, the answer is that the coefficient in front of O2 is 5.

7 0

3 years ago

Read 2 more answers

What volume would 312g of alcohol occupy

Aleksandr-060686 [28]

Answer:

Density=Mass/volume

0.91g/ml=312g/volume

Volume=343ml

Explanation:

3 0

3 years ago

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NeTakaya

No, because boats and other mechanical vehicles can spill gas and oil into the freshwater. if the freshwater is scarce already, we should not contaminate it more by risking the gas and oil spills.

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3 years ago

The fizz produced when an Alka-Seltzer® tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO3)

cestrela7 [59]

Answer:

a. The limiting reactant is $NaHCO_{3}$

b. 0.73 g of carbon dioxide are formed.

c. The grams of excess reactant that do not participate in the reaction are 0333 g.

Explanation:

You know the following reaction:

$3NaHCO_{3} +H_{3} C_{6} H_{5} O_{7}$ ⇒ $3CO_{2} +3H_{2} O+Na_{3} C_{6} H_{5} O_{7}$

First, you determine the molar mass of each compound. For that you must take into account the atomic mass of each element:

Na: 23
H: 1
C: 12
O: 16

To determine the molar mass of each compound, you multiply the most atomic of each element present in the molecule by the sub-index that appears after each number, which indicates the present amount of each element in the compound:

$NaHCO_{3}$ :23+1+12+16*3=84 g/mol
$H_{3} C_{6} HO_{7}$ :1*3+12*6+1*5+16*7= 192 g/mol
$CO_{2}$ :12+16*2= 44 g/mol
$H_{2} O$ :1*2+16= 18 g/mol
$Na_{3} C_{6} H_{5} O_{7}$ : 23*3+12*6+1*5+16*7= 258 g/mol

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), you know that 3 moles of $NaHCO_{3}$ react with 1 mole of $H_{3} C_{6} HO_{7}$ Then, taking into account the molar mass of each compound, you can calculate the reacting mass of each compound by stoichiometry:

$NaHCO_{3}$ : 252 g
$H_{3} C_{6} HO_{7}$ : 192 g

You know that in a certain experiment you have 1.40 g of sodium bicarbonate and 1.40 g of citric acid. To determine the limiting reagent apply a rule of three simple as follows:

If by stoichiometry 252 g of sodium bicarbonate react with 192 g of citric acid, how many grams of sodium bicarbonate react with 1.4 grams of citric acid?

$grams of sodium bicarbonate= \frac{1.4 g*252 g}{192 g}$

grams of sodium bicarbonate= 1.8375 g

But to perform the experiment you have only 1.4 g of sodium bicarbonate. So the limiting reagent is sodium bicarbonate.

As mentioned, the limiting reagent is sodium bicarbonate. This means that you should use 1.4 g of sodium bicarbonate for all subsequent calculations, because this compound is the reagent that will be consumed first.

Now, by stoichiometry of the reaction, you know that 3 moles of $NaHCO_{3}$ react with 3 mole of $CO_{2}$ . Then, taking into account the molar mass of each compound, you can calculate the reacting mass of each compound by stoichiometry:

$NaHCO_{3}$ : 252 g
$H_{3} C_{6} HO_{7}$ : 132 g

You make a simple rule of three: if 252 g of sodium bicarbonate form 132 g of carbon dioxide per stochetry, how many grams will form 1.4 g of sodium bicarbonate?

$grams of carbon dioxide =\frac{1.4 g * 132 g}{252 g}$

grams of carbon dioxide= 0.73 g

Then, 0.73 g of carbon dioxide are formed.

To know how much citric acid will react you apply a rule of three, taking into account as in the previous cases the stoichiometry of the reaction: If by stoichiometry 252 g of sodium bicarbonate react with 192 g of citric acid, how many grams of citric acid will they react with 1.4 g of sodium bicarbonate?

$grams of citric acid=\frac{1.4 g * 192 g}{252 g}$

grams of citric acid= 1.067 g

But you have 1.4 g of citric acid. That means that the grams you have minus the grams that react will be the grams that remain in excess and do not participate in the reaction:

grams of excess reactant=1.4 g - 1.067 g

grams of excess reactant=0.333 g

So the grams of excess reactant that do not participate in the reaction are 0333 g.

3 0

3 years ago