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abruzzese [7]
2 years ago
10

A radio controlled car travels 27 km and 28.5 minutes what is the speed of the car​

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
3 0

Answer:

56.842 km/hr

0.947 km / min

15.789 m/s

Step-by-step explanation:

speed = distance / time

let's assume your teacher wants it in km/ hr

28.5 minutes = ? hours

60 minutes = 1 hour

we can multiply both sides of 60 minutes = 1 hour by 28.5/60 to get 28.5 minutes = 28.5/60 hours

distance = 27 km

27 km / (28.5/60) hours = 56.842 km/hr

in km / minute

27 km / 28.5 minutes = 0.947 km / min

in meters/second:

1 minute = 60 seconds

28.5 minutes = ? seconds

we can multiply both sides of the first equation by 28.5 to get

28.5 minutes = 1710 seconds

27 km = ? meters

1 km = 1000 meters

we can multiply both sides of the second equation by 27 to get

27km = 27000 meters

27000 meters / 1710 seconds = 15.789 m/s

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25 now give me brainliest plz

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3 years ago
Keisha, Boris, and Jose sent a total of 126 text messages over their cell phones during the weekend. Boris sent 4 times as many
tangare [24]

Answer:

Boris=504 keisha=120

Step-by-step explanation:

First you would start off by Multiplying 4x126 the result of that is= 504 so thats how much Boris sent. To get the answer to how many jose sent you simply just subtract 6-126 and that should result in 120

5 0
3 years ago
Simplify [3(4-2)]x(16-4x3)PLS HURRY!!!!!!!!!
Lapatulllka [165]

Answer:6x*4

Step-by-step explanation:

(12-6)x(16-12)

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5 0
2 years ago
Read 2 more answers
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
5.5-3b=2b-6.25 how do you slove
olga55 [171]
Add 6.25 from 5 then you get 11.25. then you add 3b to 2b then you get 5b. the. divide 5b to 11.25 to get the answer
3 0
3 years ago
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