Answer:
60 student tickets and 40 adult tickets were sold
Step-by-step explanation:
Let s represent student tickets and a adult tickets, then the system of equations can be written as
s - a = 20 →(1)
2s + 4a = 280 → (2)
Multiply (1) by 4 and add to (2) to eliminate a
4s - 4a = 80 → (3)
Add (2) and (3) term by term
6s = 360 ( divide both sides by 6 )
s = 60
Substitute s = 60 into (1)
60 - a = 20 ( subtract 60 from both sides )
- a = - 40 ( multiply both sides by - 1 )
a = 40
Thus
60 student and 40 adult tickets were sold.
Answer:
a=6, b=-12, and c=0
Step-by-step explanation:
The standard format for the quadratic formula is ax^2+bx+c (=0).
If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.
6x^2=12x We can move over the 12x to the other side.
6x^2-12x=0 There is no visible value of c, but since there is no term without a variable, c=0
6x^2-12x+0=0
So a=6, b=-12, and c=0
Answer:
u=95
Step-by-step explanation:
To solve this problem we need to isolate 'u' variable using properties of equation.
Lets multiply by -9 the whole equation
u - -23=-8*9
Remember keys features of algebra:
- * - = +
- * += -
+ * - = -
+ * + =+
So, our equations becomes>
u+23=-72
Lets now subtract 23 to both sides
u-23=-72-23
We have u=95
Answer: 0.9104
Step-by-step explanation:
Given : A hardware store receives a shipment of bolts that are supposed to be 12 cm long.
Mean : 
Standard deviation : 
Sample size : n=10
Since, they will declare the shipment defective and return it to the manufacturer if the average length of the 100 bolts is less than 11.97 cm or greater than 12.04 cm.
So for the shipment to be satisfactory, the length of the bolts must be between 11.97 cm and 12.04 cm.
We assume that the length of the bolts are normally distributed.
Let X be the random variable that represents the length of randomly picked bolt .
For Z score : 
For x = 11.97

For x = 12.04

By using the standard normal distribution table , the probability that the shipment is found satisfactory will be :-

Hence, the probability that the shipment is found satisfactory=0.9104