True
The Perpendicular Bisector Theorem states, If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment
The answer would be positive
The ordered pair that makes both inequalities true is (4,0).
we have
y<3x-1 ----> inequality A
y > –x + 4----> inequality B
we know that
If an ordered pair is a solution to the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
Inequality A
0<3(4)-1 ----> is true
Inequality B
0> –4 + 4 ----> is true
<h3>What is inequality?</h3>
A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.
So, The ordered pair makes both inequalities true
case 2) (1,2)
Inequality A
2< 3(1) – 1
2<3-1
2<2----> is not true
So the ordered pair does not make both inequalities true
case 3) (0,4)
Inequality A
0 < 3(4) – 1
0<12-1
0<11 ----> is not true
So, the ordered pair does not make both inequalities true
case 4) (2,1)
Inequality A
1< 3(2) – 1
1<6-1
1<5----> is true
Inequality B

----> is not true
So the ordered pair does not make both inequalities true.
To learn more about the inequalities visit:
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Answer:

Step-by-step explanation:
Since both the original and transformed graph have the same x value for their vertex, there was no horizontal shift. However the vertex shifted up. Specifically it shifted up 5 units. Therefore:

The plus 5 performs a translation up 5 units. Plugging in for f(x) it can be seen that:
