1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11
2. 2x + 5x = 8x
3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2
4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y
5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
-4y^3 - 3y^2 + 5y
The answer to your problem is 2
Answer:
∠A = ∠D (**but very important Δ ABC has to be congruent to Δ DEF)
Step-by-step explanation:
It will help if you draw the triangles out and label the same sides. Then according to the side-angle-side (SAS) rule, ∠A should be equal to ∠D
im assuming i just pick two angles cause i cant see the options? two 90 degree angles.
and my name is teagan too :D
Answer:
c
Step-by-step explanation:
