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dlinn [17]
3 years ago
13

Gina looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one

wall in the plan is 17 inches. The length of the diagonal of the floor of the room in the plan is approximately 18.79 inches.
Is the room in the shape of a square? Explain how you determined your answer. Show all your work.
Mathematics
2 answers:
Alja [10]3 years ago
8 0
No. A square has equal sides that are perpendicular and parallel. I'm guessing this room resembles some other figure.
disa [49]3 years ago
6 0
Your shape is a cube.
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3 years ago
-4(x+9)+-16 PLEASE ANSWER FAST
PIT_PIT [208]

Answer:

-4x-52

Step-by-step explanation:

-4(x+9)+(-16)

-4x-36-16

-4x-52

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3 years ago
Giant is selling Cereal at $8 for 3 boxes.what is the cost per box?
Zolol [24]

Answer:

$2.67

Step-by-step explanation:

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3 years ago
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Item 3<br> Is this function linear or nonlinear?<br><br> y=2x²−4<br><br> linear<br><br> nonlinear
kodGreya [7K]

Answer:

B.nonlinear

Step-by-step explanation:

4 0
3 years ago
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SOMEONE HELP?!! ASAP !! I’ll give brainliest!! Please and ty !!
dsp73

Answer:

(\pi 4^2 (9))-(\pi 2^2 (9))

and

339.292 cm^3

Step-by-step explanation:

This question is simple once you break it down.

Let's concentrate on the outer cylinder.

First, find the volume of the outer cylinder.

The volume of a cylinder is expressed as: V = \pi r^2 h  

Gathering information from the diagram..

d = 8 cm

h = 9 cm

You can get the radius from the diameter by just dividing the diameter by 2.

r = \frac{8}{2}=4

r = 4

Plug everything into the volume equation.

V = \pi 4^2 (9)

Don't solve just yet!

Now, find the volume of the inner cylinder.

Do the exact same thing as you did for the outer cylinder.

d = 4 cm

h = 9 cm

r = \frac{4}{2}=2

r = 2

Plug everything into the volume equation..

V = \pi 2^2 (9)

The question asks for an expression to represent the volume of the large cylinder after the cylindrical hole is removed. This means you need to subtract the volume of the cylindrical hole from the volume for the large cylinder.

Again, the volume for the large cylinder is V = \pi 4^2 (9) and the volume for the cylindrical hole is V = \pi 2^2 (9)

This means..

(\pi 4^2 (9))-(\pi 2^2 (9))

That is your answer to the first part of the question.

For the second part, just solve.

(\pi 4^2 (9))-(\pi 2^2 (9))

(\pi*16*9)-(\pi*4*9)

(\pi*144)-(\pi*36)

144\pi-36\pi

108\pi

339.292

Don't forget the units.

339.292 cm^3

Hope this helped you!

3 0
3 years ago
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