Question

Tetraphosphorus decaiodide is represented by which formula? A) P3I10 B) P4I10 C) P3I8 D) P4I8

Answer 1

Answer: B) $P_4I_{10}$

Explanation: $P_4I_{10}$ is a covalent compound because sharing of electrons takes place between phosphorous and iodine. Both the elements are non-metals and hence, will form covalent bond.

The nomenclature of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written then, and a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms , 'tetra' for 4 atoms and so on.

So, the IUPAC name for $P_4I_{10}$ is tetraphosphorus decaiodide.

Answer 2

The answer is B.

Tetraphosphorus is written as P4, and decaiodide as I10, so when you put them together, it's P4I10