144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.
<h3>What is Ideal Gas Law ? </h3>
The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.
PV = nRT
where,
P = Presure
V = Volume in liters
n = number of moles of gas
R = Ideal gas constant
T = temperature in Kelvin
Here,
P = 1 atm [At STP]
R = 0.0821 atm.L/mol.K
T = 273 K [At STP]
Now first find the number of moles
F₂ + CaBr₂ → CaF₂ + Br₂
Here 1 mole of F₂ reacts with 1 mole of CaBr₂.
So, 199.89 g CaBr₂ reacts with = 1 mole of F₂
1.28 g of CaBr₂ will react with = n mole of F₂
![n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B1.28%5Cg%20%5Ctimes%201%5C%20%5Ctext%7Bmole%7D%7D%7B199.89%5C%20g%7D)
n = 0.0064 mole
Now put the value in above equation we get
PV = nRT
1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K
V = 0.1434 L
V ≈ 144 mL
Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.
Learn more about the Ideal Gas here: brainly.com/question/20348074
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It's 1. Melting a substance. The rest are chemical changes
Answer:
![\boxed{\text{25. 20 L; 26. 49 K}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B25.%2020%20L%3B%2026.%2049%20K%7D%7D)
Explanation:
25. Boyle's Law
The temperature and amount of gas are constant, so we can use Boyle’s Law.
![p_{1}V_{1} = p_{2}V_{2}](https://tex.z-dn.net/?f=p_%7B1%7DV_%7B1%7D%20%3D%20p_%7B2%7DV_%7B2%7D)
Data:
![\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcrrcl%7Dp_%7B1%7D%26%20%3D%26%20%5Ctext%7B100%20kPa%7D%5Cqquad%20%26%20V_%7B1%7D%20%26%3D%20%26%20%5Ctext%7B10.00%20L%7D%20%5C%5Cp_%7B2%7D%26%20%3D%26%20%5Ctext%7B50%20kPa%7D%5Cqquad%20%26%20V_%7B2%7D%20%26%3D%20%26%20%3F%5C%5C%5Cend%7Barray%7D)
Calculations:
![\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D100%20%5Ctimes%2010.00%20%26%20%3D%26%2050V_%7B2%7D%5C%5C1000%20%26%20%3D%20%26%2050V_%7B2%7D%5C%5CV_%7B2%7D%20%26%20%3D%20%26%5Ctextbf%7B20%20L%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20new%20volume%20will%20be%20%7D%20%5Cboxed%7B%5Ctextbf%7B20%20L%7D%7D)
26. Ideal Gas Law
We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.
pV = nRT
Data:
p = 101.3 kPa
V = 20 L
n = 5 mol
R = 8.314 kPa·L·K⁻¹mol⁻¹
Calculation:
101.3 × 20 = 5 × 8.314 × T
2026 = 41.57T
![T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B2026%7D%7B41.57%7D%20%3D%20%5Ctextbf%7B49%20K%7D%5C%5C%5C%5C%5Ctext%7BThe%20Kelvin%20temperature%20is%20%7D%5Cboxed%7B%5Ctextbf%7B49%20K%7D%7D)
Answer:
a) 6312.12 lbm
b) D = 11.843 inch
Explanation:
GIVEN DATA:
Height of person = 1.89 m = 74.41 inch
mass of person m = 89 kg = 196.211 lbm
a) person earth weight =mg
where g is acceleration due to gravity = 32.17 ft/sec^2
![= 196.211\times 32.17 = 6312.12 lbm](https://tex.z-dn.net/?f=%20%3D%20196.211%5Ctimes%2032.17%20%3D%206312.12%20lbm)
b) waist to height ratio = 0.5
![waist\ to\ height\ ratio = \frac{circumference\ of\ the\ waist}{height\ of\ the\ person}](https://tex.z-dn.net/?f=waist%5C%20to%5C%20%20height%5C%20%20ratio%20%3D%20%5Cfrac%7Bcircumference%5C%20of%5C%20the%5C%20waist%7D%7Bheight%5C%20of%5C%20the%5C%20person%7D)
circumference of waist =![height\ of\ person \times waist\ to\ height ratio](https://tex.z-dn.net/?f=%20height%5C%20%20of%5C%20%20person%20%5Ctimes%20waist%5C%20to%5C%20height%20ratio)
![= 74.41 inch \times 0.5](https://tex.z-dn.net/?f=%3D%2074.41%20inch%20%5Ctimes%200.5)
=37.21 inch
we know that circumference is given as ![= 2\pi r\ or\ \pi D= 37.21](https://tex.z-dn.net/?f=%3D%202%5Cpi%20r%5C%20or%5C%20%20%5Cpi%20D%3D%2037.21)
D = 11.843 inch