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maria [59]
3 years ago
5

What volume change occurs to a 400.0 mL gas sample as the temperature increases from 22.0 °C to 30.0°C?

Chemistry
1 answer:
nasty-shy [4]3 years ago
4 0
V₁ = 400.0 mL

T₁ = 22.0ºC + 273 = 295 K

V₂ = ?

T₂ = 30.0ºC + 273 = 303 K

V₁ / T₁ = V₂ / T₂

400.0 / 295 = V₂ / 303

295 x V₂ = 400.0 x 303

295 V₂ = 121200

V₂ = 121200 / 295

V₂ = 410.84 mL

hope this helps!
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Explanation:

Moles of metal,

=

4.86

⋅

g

24.305

⋅

g

⋅

m

o

l

−

1

=

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o

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.

Moles of

H

C

l

=

100

⋅

c

m

−

3

×

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⋅

m

o

l

⋅

d

m

−

3

=

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m

o

l

Clearly, the acid is in deficiency ; i.e. it is the limiting reagent, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal.

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0.200

m

o

l

acid react, then (by the stoichiometry), 1/2 this quantity, i.e.

0.100

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of dihydrogen will evolve.

So,

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o

l

dihydrogen are evolved; this has a mass of

0.100

⋅

m

o

l

×

2.00

⋅

g

⋅

m

o

l

−

1

=

?

?

g

.

If 1 mol dihydrogen gas occupies

24.5

d

m

3

at room temperature and pressure, what will be the VOLUME of gas evolved?

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