1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yuradex [85]
4 years ago
11

5. It is given that -2,4, a, b and care five consecutive terms of a geometric progression. Find the value of c.

Mathematics
1 answer:
vlada-n [284]4 years ago
3 0

Answer:

c = - 32

Step-by-step explanation:

The common ratio r of the sequence is

r = \frac{a_{2} }{a_{1} } = \frac{4}{-2} = - 2

To find the next term in the sequence multiply the previous term by r

a = 4 × - 2 = - 8

b = - 8 × - 2 = 16

c = 16 × - 2 = - 32

You might be interested in
Help me please 25 points.
sveticcg [70]

The answer i got is VP<------------->

AKA the first option

i hope this is right  

4 0
3 years ago
Read 2 more answers
9. The ticket at right has a perimeter of 42 cm.
Liula [17]

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.

I've added the image of the ticket as an attachment.

(a) The missing side length

From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.

So, we have:

Perimeter =2\times 11 + 4 \times L

This gives

2\times11 + 4 \times L = 42

22 + 4 \times L = 42

Collect like terms

4 \times L = 42-22

4 \times L = 20

Divide both sides by 4

L =5cm

(b) The length of the gold lines

There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).

So, the length of the gold line is:

Gold = 4 \times L

Gold = 4 \times 5cm

Gold = 20cm

(c) The number of gold ink bottles.

n = 200 --- number of tickets

The length of all gold line in the 200 tickets is:

Length = 200 \times Gold

Length = 200 \times 20cm

Length = 4000 cm

Length = 4000 \times 0.01m ---- convert to meters

Length = 40m

Given that:

Bottle = 20m --- 1 bottle for 20 m

The number of bottles (n) is:

n = \frac{Length}{Bottles}

n = \frac{40m}{20m}

n = 2

Hence, 2 bottles of gold ink are enough.

Read more about perimeters at:

brainly.com/question/6465134

4 0
3 years ago
Julio says "If you subtract 13 from my number and multipy the difference by -3 the result is -45" what is Julio's number
ICE Princess25 [194]

Answer:28

Step-by-step explanation:

Julio's number is x

(X-13)*-3=-45

Divide by -3

X-13=15

Add13 to both sides

x=28

6 0
3 years ago
Can someone help me find the domain of this function please ?
ratelena [41]

Answer: It is A=-1<x<-6 is the domain

4 0
4 years ago
Do you use the greatest common factor or the least common multiple to add two fractions? In this example what is it? 4/5+5/6 lea
Alenkinab [10]

Answer:

30 is the least common factor or lcm

Step-by-step explanation:

when adding fractions you always have to find the lcm

8 0
3 years ago
Other questions:
  • What's the pattern for 1,3,5,7,5,3,1,3
    5·1 answer
  • I need help with 1 2 3 &amp; 4 please help
    8·1 answer
  • Type the algebraic equation for this statement. Let a represent the unknown number.
    15·1 answer
  • There are 13 boys and 15 girls in Ms. Green’s 3rd period math class. Five girls and four boys have already been called on today.
    11·1 answer
  • N + 7n -5=3 what is n =
    8·2 answers
  • Six less than the product of 14 and a number
    10·1 answer
  • Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
    5·1 answer
  • Solve for f(3) given f(x)= -4x + 5*<br> (10 Points)
    10·1 answer
  • Plz Help me!!!<br> will mark brainliest!!
    8·1 answer
  • Now that Anna's Boutique has merged with another store, the members of its staff make $26. That is 30% more than they historical
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!