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stellarik [79]
2 years ago
10

Pls answer this question

Mathematics
1 answer:
inn [45]2 years ago
3 0

Answer:

1.9391 is ur questions answer

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The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is r
svp [43]

Answer:

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.

This means that a = 50, b = 52

If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

P(51.5 \leq X \leq 51.7) = \frac{51.7 - 51.5}{52 - 50} = \frac{0.2}{2} = 0.1

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.

3 0
3 years ago
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