Answer:
(9*2)*5
Step-by-step explanation:
No matter if you move the parenthesis it stays the same answer :)
Answer:
Domain = {x : x ≠ 4 , -4} or (-∞ , -4) ∪ (-4 , 4) ∪ (4 , ∞)
Step-by-step explanation:
<u>TO FIND :-</u>
- Domain of
![C(x) = \frac{x + 9}{x^2 - 16}](https://tex.z-dn.net/?f=C%28x%29%20%3D%20%5Cfrac%7Bx%20%2B%209%7D%7Bx%5E2%20-%2016%7D)
<u>SOLUTION :-</u>
Domain of a function is a value for which the function is valid.
The function
is valid until the denominator is 0.
So make sure that the denominator must not be 0.
![=> x^2 - 16 > 0](https://tex.z-dn.net/?f=%3D%3E%20x%5E2%20-%2016%20%3E%200)
Find the values of x for which the denominator becomes 0. To find it , you'll have to solve the above inequality.
![=>x^2 - 16 + 16 > 0 + 16](https://tex.z-dn.net/?f=%3D%3Ex%5E2%20-%2016%20%2B%2016%20%3E%200%20%2B%2016)
![=> x^2 > 16](https://tex.z-dn.net/?f=%3D%3E%20x%5E2%20%3E%2016)
![=> x > \sqrt{16}](https://tex.z-dn.net/?f=%3D%3E%20x%20%3E%20%5Csqrt%7B16%7D)
![=> \boxed{x > 4} \: or \:\boxed{x > -4}](https://tex.z-dn.net/?f=%3D%3E%20%5Cboxed%7Bx%20%3E%204%7D%20%5C%3A%20or%20%5C%3A%5Cboxed%7Bx%20%3E%20-4%7D)
We can say that <u>4 & -4 can't be domains</u> because these values will make the function undefined.
Now try putting values of x such that -4 < x < 4. You'll observe that the function will be valid for all those values of x between -4 & 4.
<u>CONCLUSION :-</u>
The function will be valid for any value of 'x' except 4 & -4. So in :-
Interval notation , it can be written as → (-∞ , -4) ∪ (-4 , 4) ∪ (4 , ∞)
Set builder notation , it can be written as → {x : x ≠ 4 , -4}
Answer:
the answer is c 50x +11
Step-by-step explanation:
The statements that are true about this graph are the pumpkin grew at a rate of 6 ounces per week, and in 3 weeks the pumpkin grew to a total of 18 ounces.
<h3>What does 3,18 mean?</h3>
The number 3 indicates the value in x, while the number 18 indicates the value of y.
- x = 3 weeks (time)
- y = 18 ounces (weight)
<h3>What statements are true about this graph?</h3>
- It is true the rate was 6 ounces per week (18 ounces/6 = 3).
- It is true by the end of week 3 the weight was 18 ounces.
Learn more about graphs in: brainly.com/question/16608196
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