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nexus9112 [7]
3 years ago
15

What is the range of function f(x)=1/2sqrtx?

Mathematics
1 answer:
enyata [817]3 years ago
4 0
X cannot be negative as a negative value has no square root 
range is  0=< x < infinity
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6. Let A and B be nxn matrices . Compute (A + B) (A + B). Explain all steps.
Pie

Answer:

(A+B)(A+B)=A.A+B.A+A.B+B.B

Step-by-step explanation:

Given that matrices A and B are nxn matrices

We need to find (A+B)(A+B)

For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.

We know that that in matrices AB is not equal to BA.

Now find  

(A+B)(A+B)=A.A+B.A+A.B+B.B

So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.

So (A+B)(A+B)=A.A+B.A+A.B+B.B

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3 years ago
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Question 2 i have no idea with functions
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Answer:

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but when it limits the domain it gonna be

(-1,0,3,8)

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