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yaroslaw [1]
3 years ago
5

How do I do question 5. ?

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
The first one shown, 400/2, is showing the point on the graph where she walks 400 ft in 2 minutes. In order to find the next proportion, you just have to look two minutes over which in this case is 800 ft for 4 minutes... written 800 over 4.
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navik [9.2K]

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See below

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The first two questions are slope = 0

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2 years ago
Read 2 more answers
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
oksian1 [2.3K]

Answer:

17 seconds

Step-by-step explanation:

Solution:-

The trajectory of a rocket launched is modeled by a parabolic path via a quadratic equation as follows:

                               y = -16x^2 + 266x +102

Where,

                   y: The height of the rocket from ground

                   x: The time taken since rocket launch

We are to determine the time ( x ) it takes for the rocket to hit the ground. This can be determined by setting the quantity ( y ) to zero as follows

                             y = -16x^2 + 266x +102 = 0\\\\ -16x^2 + 266x +102 = 0

solve the quadratic equation using quadratic formula as follows:

                             x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-266 +/- \sqrt{266^2 - 4*(-16)*(102)} }{2*(-16)} \\\\x = \frac{-266 +/- 278 }{-32} \\\\x = 8.3125 +/- 8.6875\\\\x = 17 , -0.375

Answer: Ignore the negative value for time " -0.375 ". Hence, the rocket hits the ground at time t = 17 seconds

6 0
3 years ago
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