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yaroslaw [1]
3 years ago
5

How do I do question 5. ?

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
The first one shown, 400/2, is showing the point on the graph where she walks 400 ft in 2 minutes. In order to find the next proportion, you just have to look two minutes over which in this case is 800 ft for 4 minutes... written 800 over 4.
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Construct a triangle ABC where BC =4cm ,B=60° and AB+AC=6cm
Fittoniya [83]

Answer:

Below is the step-by-step explanation.

Step-by-step explanation:

To determine:

Construct a triangle ABC

Information Fetching and Information Steps:

From the given data,

  • BC\:=\:4\:cm
  • B=60^{\circ }
  • AB+AC=6\:cm

Procedure:

  • First draw a line segment BC\:=\:4\:cm
  • Then construct angle of m ∠ 60^{0}  at B on BC.
  • Taking B as center with 6\:cm radius, draw an arc which cuts the ray of  m ∠ 60^{0} at X.
  • Then Join X and C.
  • The draw a perpendicular bisector of XC.
  • Wherever this perpendicular bisector intersect BX, name that point as A
  • Join A and  C.

Thus, ∆ ABC will be a required triangle.

Keywords: triangle, perpendicular bisector, angle

Learn more about triangle construction form brainly.com/question/7411225

#learnwithBrainly

8 0
3 years ago
Find the area of the shape shown below
sveticcg [70]

Answer:

63

Step-by-step explanation:

3x3= 9x7= 63

4 0
3 years ago
=
slamgirl [31]

Answer:D

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 8.5%/100 = 0.085 per year

putting time into years for simplicity

6 months ÷ 12 months/year = 0.5 years

then, solving our equation

I = 10000 × 0.085 × 0.5 = 425

I = $ 425.00

on a principal of $ 10,000.00

at a rate of 8.5% per year

for 0.5 years (6 months) is $ 425.00

3 0
2 years ago
A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.
Reptile [31]

Answer:

a.P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}

Step-by-step explanation:

We are given that a linear differential equation

y''+2y=e^{3x}+x^3

We have to find the particular solution

P.I=\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}

P.I=\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}

P.I=\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3

P.I=\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0} (higher order terms can be neglected

P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.Characteristics equation

D^2+2=0

D=\pm\sqrt2 i

C.F=C_1cos \sqrt2x+C_2 sin\sqrt2 x

G.S=C.F+P.I

G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)

3 0
3 years ago
A 3 foot wide painting should be centered on 13 foot wide wall how many feet should be on each side of the painting
VLD [36.1K]

Answer:

5 feet of wall should be on each side of the painting.

Step-by-step explanation:

Given that a 3 foot wide painting should be centered on 13 foot wide wall, to determine how many feet should be on each side of the painting, the following calculations must be performed:

(13 - 3) / 2 = X

10/2 = X

5 = X

Therefore, 5 feet of wall should be on each side of the painting.

5 0
3 years ago
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