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vredina [299]
3 years ago
11

A professional basketball player participated in 1,558 games in his career. He randomly chose eight games to determine the numbe

r of points he made per game, as shown below. 27, 19, 29, 19, 25, 27, 25, 27 If the sample was representative of his entire career, what was the mode of the number of points per game?
Mathematics
1 answer:
DENIUS [597]3 years ago
4 0

Answer:

27 is the mode of the number of points per game.  

Step-by-step explanation:

We are given the following in the question:

Total number of games = 1558

Sample size = 8

Sample of points made per game:

27, 19, 29, 19, 25, 27, 25, 27

Sorted data:

19, 19, 25, 25, 27, 27, 27, 29

Mode:

  • It is the most frequent observation in the sample.

Since 27 repeats itself three times that is highest repeating number, the mode of the data is 27.

27 is the mode of the number of points per game.

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NISA [10]
\bf ~~~~~~~~~~~~\textit{function transformations}
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\\\\
~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\\\
f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
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f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
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with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

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8 0
3 years ago
B.
Helen [10]

Answer:

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

Step-by-step explanation:

The given figure consists of three triangles

1. ΔUJN, 2. ΔUGN, and 3. ΔUJG

Whereby segment UN is perpendicular to segment JG, we have;

ΔUJN and ΔUGN are right triangles

∴ ∠UNJ = ∠UNG = 90° by definition of segment UN being perpendicular to segment JG

NU ≅ NU by reflexive property

Whereby UN bisects ∠JUG and segment JG, we have;

JN = GN by definition of a bisected segment

Therefore, we have;

1. ΔUJN ≅ ΔUGN by SAS rule of congruency

2. Side Angle Side Rule of congruency

3. JN ≅ GN, ∠JUN ≅ ∠NUG, ∠UNJ ≅ ∠UNG, NU ≅ NU

4. UN bisects angle ∠JUG and UN bisects segment JG

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3 years ago
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Answer:

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Step-by-step explanation:

√175 ≈ 13.2 . . . units

The area of a square is the square of the edge length. Hence, the edge length is the square root of the area.

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shepuryov [24]

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11/2

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Multiply by 2/2 to remove the decimal.

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