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raketka [301]
3 years ago
9

If the common difference in an arithmetic sequence is 4, and the 20th term is 36, what is the first term?

Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0
4 difference, subtract 20 point - 1st point, =19, 19 places x difference of 4= 76 more or less than 36. More would be 112, less would be -40. A and C are both 40 while choice B = the difference so I'd say it's supposed to be 1 of the 40's but it's missing the negative sign
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863.141 in expanded form
Neporo4naja [7]
800
+ 60
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4 0
3 years ago
If 3/4 of the class likes soda and 3/5 of those who like soda prefer Coke, what PERCENT of the whole class that likes Coke?
katen-ka-za [31]

Answer:

For soda =3/4

For coke= 3/5 X 3/4=9/20

Whole class is 1....

Therefore X% of 1 =9/20

Solving :

X/100 X 1 =9/20

X/100=9/20

20X =900

X= 900/20 = 45%

8 0
3 years ago
The table shows values for functions f(x) and g(x) .
Bas_tet [7]

Answer:

There is no correct answer

Step-by-step explanation:

4x+20

2x+6

4x+20=2x+6

4x–2x=6–20

2x=–14

x=–7

5 0
4 years ago
13. Reason abstractly. If you subtract a negative number from
Kitty [74]
Subtracting a negative number is like removing debt. When you remove debt, you effectively gave someone money and the value of their bank account increased.

Another answer is that “subtraction is addition of the opposite,” so subtracting a negative number is really adding a positive number, which again causes the other number to increase.
8 0
3 years ago
Read 2 more answers
HELP PLEASE! Can you please explain so I can understand how it was completed?
nlexa [21]

Answer:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

Step-by-step explanation:

Hello!

We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.

We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:

  • The radial coordinate which is often denoted by r.
  • The angular coordinate by θ.

So we need to find r and θ. So we know that:

r=\sqrt{x^{2}+y^{2}}       (1)

x = rcos(θ)                                   (2)

x = rsin(θ)                                    (3)

From the statement we know that (x, y) = (3, -3).

Using the equation (1) we find that:

r=\sqrt{x^{2}+y^{2}}=\sqrt{3^{2}+(-3)^{2}} = 3\sqrt{2}

Using the equations (2) and (3) we find that:

3 = rcos(θ)

-3 = rsin(θ)

Solving the system of equations:

θ= -45

Then:

r = 3\sqrt{2}[/tex]

θ= -45 or 315

Notice that  there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.

So, the solution is:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

4 0
3 years ago
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