Question

(X^2)+(y^2)+10x-6y+18=0

Answer 1

x² + y² – 10x + 6y + 18 = 0 x² – 10x + y² + 6y + 18 = 0 x² – 10x + 25 - 25 + y² + 6y + 9 - 9 + 18 = 0 (x-5)² + (y+3)² -16 = 0 (x-5)² + (y+3)² = 16 (x-5)² + (y+3)² = 4² Center at (5,-3) radius = 4 Part 2 1. Complete the square for x and y 2. Put in the format for a circle. (x-h)² + (y-k)² = r², center at (h,k) with radius = r