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mrs_skeptik [129]
4 years ago
15

Which process is used to make lime (calcium oxide) from limestone (calcium carbonate)?​

Chemistry
1 answer:
Ber [7]4 years ago
3 0

Answer:

Explanation:

Calcium oxide is fromed by the decomopostion of CaCO3 at high temperature.

CaCO3   ------> CaO  +CO2

Hope this helps you

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Suppose you were doing the experiment with a 50 mL syringe. How many mL would you pull the plunger for each reading?
goldfiish [28.3K]
50 mL would be the answer
5 0
3 years ago
If sock type A is pulled first, sock type B second, and sock type C third, the fourth sock type must match one of A, B, or C.
alexandr1967 [171]

Answer:

a

Explanation:

sock type a is first then other sock types

5 0
3 years ago
Help me this, I only have 10 minutes to answer!!!!
Nana76 [90]

Answer:sedimentary

Explanation:

3 0
3 years ago
A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution
alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

<u>Explanation:</u>

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $\frac{mass}{molar mass}

       = $\frac{318.6 g}{342.3 g/mol}

      = 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $\frac{mass}{density}

             = $\frac{4905 g }{1000 g/L}

          = 4.905 L

Now we can find the molarity = $\frac{moles}{Volume(L)}

                               =  $\frac{0.93 moles}{4.905 L}

                              = 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}

= 1200 g

Now we have to find out the amount of HCl in grams as,

$\frac{1200g \times 39 g HCl }{100 g solution}

= 468 g HCl

Now we have to find the number of moles,

moles = $\frac{468 g}{36.46 g/mol}

           = 12.8 moles

Molarity of HCl = $\frac{12.8 moles}{1 L }

                          = 12.8 M

So the molarity of HCl is 12.8 M.

6 0
3 years ago
How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2
Airida [17]

Answer:

calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.

1 mol contains 310 grams

2.3*10^-4 moles contain  2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.

6 0
3 years ago
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