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valentina_108 [34]
3 years ago
13

How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2

Chemistry
1 answer:
Airida [17]3 years ago
6 0

Answer:

calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.

1 mol contains 310 grams

2.3*10^-4 moles contain  2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.

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Sodium Sulfate = Na2(SO4) meaning there are two ions of Na+ in one mole of Sodium Sulfate the M stands for Molarity, defined as Molarity = (moles of solute)/(Liters of solution), So if the Na2SO4 solution is 3.65M that means one Liter of has 3.65 moles of Na2SO4, the stoichiometry of Na2SO4 shows that there would be two Na+ ions in solution for every one Na2SO4.

Therefore if 3.65 moles of Na2SO4 was to dissolve, it would produce 7.3 moles of Na+, and since this is still a theoretical solution, we can assume 1 L of solution.

Finally we find [Na+] = 2*3.65 = 7.3M

Use the same logic for parts b and c




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4 years ago
As you move down through the family of alkali metals, the first ionization energy ________ because
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A block of metal has a mass of 0.0694 kg. It displaces 3.6 mL of water. What is it’s density in g/cm^3
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Answer:

19.28 g/cm^3 to the nearest hundredth.

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