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laila [671]
3 years ago
7

If sock type A is pulled first, sock type B second, and sock type C third, the fourth sock type must match one of A, B, or C.

Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

a

Explanation:

sock type a is first then other sock types

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Ms. Clark added a spoonful of baking soda and then poured a little vinegar into the cup. We observed fizzing and bubbling. Based
leva [86]

Answer:

we know that it was the vinegar and baking soda because gas had been created, the gas was held within the bubbles. the gas that was created was called Carbon Dioxide or CO2

7 0
3 years ago
Dr. Terror has developed a new alloy called Ultranomium. He is testing a bar that is 1.25 m1.25 m long and has a mass of 382 g.3
MrRissso [65]

Answer:0.8742j/g°C

Explanation: SOLUTION

GIVEN

length of bar=1.25m

mass 382g

temperature= 20°C to 288°C

Q=89300J

Specific Heat Capacity  will be calculated using

Q=mC∆T

where

C = specific heat capacity

Q = heat

m = mass

Δ T = change in temperature

C=Q/ m∆T

=89300/382X(288-20.6)

=0.8742j/g°C

4 0
3 years ago
Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
What force must act on a 150 kg mass to give it an acceleration of 30 m/s squared? F=ma
Helga [31]

Answer:

its 120

Explanation:

i did it :)

4 0
3 years ago
Scientists group similar organisms together through a process called …..
Bond [772]

Answer:

plz i need to ask another question i hope u understand

Explanation:

4 0
3 years ago
Read 2 more answers
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